How to Calculate change in volume produced by a piston?

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To calculate the change in volume produced by a piston, the equation ∆V = A × ∆d is used, where A is the cross-sectional area and ∆d is the distance the piston moves. The area is given as 1 x 10^-16 m², while the distance must be converted from nanometers to meters, resulting in 1.7 x 10^-6 m. After ensuring the units match, the volume change is calculated as 1.7 x 10^-22 m³. The discussion also highlights the importance of unit consistency and proper notation in scientific calculations. Understanding these fundamentals is crucial for solving related physics problems accurately.
  • #31
spacealgae said:
Awesome! Thank you very much! So now that's all figured out how would I multiply that by the atmospheric pressure, 0.25 A t m? Would I convert the A t m to scientific notation and then multiply?
It's a little more involved than that.

First, what are the units of work?

BTW, the unit 'atmosphere' is abbreviated 'atm.', not 'a t m'.
 
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  • #32
I believe that units of work are in Joules. And sorry, I know it's 'atm', not 'a t m', but that's just how my homework had it, so I thought I just would just keep it like that. An error in my homework grammar, I guess.
 
  • #33
spacealgae said:
I believe that units of work are in Joules.

Yes. But joules are known as derived units in SI, which means they are made up of other fundamental units. What are the fundamental units which make up a joule?
 
  • #34
spacealgae said:
So, once I convert 1700nm to meters, that would be 1.7x10^-6.
Again, you're omitting the units in your answer. 1.7 x 10-6 in what units?

When you're working problems in physics, it's very important to keep track of the units.
 
  • #35
spacealgae said:
Area of piston=1x10^-16m^2
Can someone convince me that an exercise with such a "piston" is for real ?

:rolleyes:
 
  • #36
Sounds like some sort of nano-machine.
 

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