How to Calculate Eº for 2Cu⁺(aq) → Cu²⁺(aq) + Cu(s)?

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To calculate Eº for the reaction 2Cu⁺(aq) → Cu²⁺(aq) + Cu(s), the standard reduction potential for Cu⁺ to Cu²⁺ is needed, which is -0.15V. The given Eº for Cu⁺ to Cu(s) is 0.52V. Using these values, the overall cell potential can be determined by combining the half-reactions. The standard cell potential for the desired reaction can then be calculated. This approach utilizes standard potential reduction tables for accurate results.
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Given E^{0}=0,52V for

Cu^{+}(aq) + e^{-} --> Cu(s)

Calculate E^{0} for the following reaction at 25ºC, 1atm.

2Cu^{+}(aq) --> Cu^{2+}(aq) + Cu(s)

Any ideas?
 
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Is that all the data you're given? Don't you need the E^{0} for Cu+ => Cu2+?
 


While doing these exercises we can check the standart potential reduction table.

E0 for Cu+ => Cu2+ + 1e- is -0,15V

What would you do then?
 
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