How to calculate effective resistance?

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To calculate effective resistance between points X and Y, one participant suggests that no current flows through a 20-ohm resistor, leading to a conclusion of 10 ohms. For the resistance between A and D, another participant attempts to calculate it as 30 ohms using a combination of series and parallel resistance formulas but finds it complicated. They emphasize the use of Ohm's Law and Kirchhoff's Voltage Law for solving circuits, suggesting that linear algebra may be necessary for complex configurations. The discussion also mentions the Wheatstone bridge concept, indicating that applying the superposition theorem can simplify the analysis. Effective resistance calculations can involve both theoretical understanding and practical application of circuit laws.
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Homework Statement


There are two images:-
Resistance- Calculate effective resistance between X and Y
Resistance1- Calculate effective resistance between A and D



The Attempt at a Solution



Resistance- I don't think any current passes through the 20 ohm resistor so it seems 10 ohm to me. what do you say?

Resistance1- is it right??
10+10+(1/(2/20))
=30 ohm?
 

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I don't think you can solve these with ordinary resistance reduction, at least it is too complicated for me to try. I used ohm's law, kirchhoffs voltage law and constraints. You know that the if you take any loop that the total voltage is zero, and when all the voltage loops are accounted for you can use linear algebra to solve for the system.
 
Mindscrape said:
I don't think you can solve these with ordinary resistance reduction, at least it is too complicated for me to try. I used ohm's law, kirchhoffs voltage law and constraints. You know that the if you take any loop that the total voltage is zero, and when all the voltage loops are accounted for you can use linear algebra to solve for the system.

I will be glad if you explain to me what you want to convey...
 
Its simply a wheatstone bridge redrawn ...
 
1.apply superposition theroem
2.u will egt current and potential difference across the (upper and lower) ,and the (first and last) resistor are the same .
3 10 \Omega
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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