How to Calculate Heat Current in a Spherical Shell?

Click For Summary
SUMMARY

The discussion focuses on calculating the total heat current through a spherical shell with inner radius r_a and outer radius r_b, where the temperatures at the inner and outer surfaces are T_a and T_b, respectively. The derived equation for heat current is H = -kA(T_b - T_a) / (r_b - r_a), with A defined as A(r) = 4πr². The solution involves treating the problem as a separable differential equation, leading to the final expression H = k * 4π * (T_b - T_a) / (1/r_b - 1/r_a), confirming the correct approach to the problem.

PREREQUISITES
  • Understanding of thermal conductivity and its role in heat transfer
  • Knowledge of calculus, specifically separable differential equations
  • Familiarity with spherical geometry and surface area calculations
  • Basic principles of thermodynamics related to heat transfer
NEXT STEPS
  • Study the derivation of Maxwell's equations and their applications in heat transfer
  • Explore advanced topics in thermodynamics, focusing on heat conduction in various geometries
  • Learn about numerical methods for solving differential equations in thermal analysis
  • Investigate the impact of varying thermal conductivity on heat transfer in spherical shells
USEFUL FOR

Students and professionals in physics and engineering, particularly those focusing on thermodynamics and heat transfer analysis in spherical geometries.

TheDemx27
Gold Member
Messages
169
Reaction score
13

Homework Statement


A spherical shell has inner and outer radii r_a and r_b, respectively, and the temperatures at the inner and outer surfaces are T_a and T_b. The thermal conductivity of he shell material is k. Derive an equation for the total heat current thought the shell in the steady state. Then calculate the temperature as a function of r, the distance from the center of the shell.

Homework Equations


H=-kA(T_b-T_a)/(r_b-r_a)

The Attempt at a Solution


I know that I'm supposed to use calculus somehow, I write the area A as a function of r, A(r)=4pi*r^2. I don't know what to do from there
 
Physics news on Phys.org
Oh I think I got it. It is just a separable differential equation, right?
 
Hint: "Maxwell."
 
That does nothing for me. I was only ever taught the derived forms of maxwell's equations...

Treating it as a separable differential equation H=-kA*(dT/dr) I got
H=k*4pi*(T_b-T_a)/(1/r_b-1/r_a)
 
Last edited:
TheDemx27 said:
That does nothing for me. I was only ever taught the derived forms of maxwell's equations...

Treating it as a separable differential equation H=-kA*(dT/dr) I got
H=k*4pi*(T_b-T_a)/(1/r_b-1/r_a)
This result is right on target, and is the way I would have solved the problem too. Nice job.
 
  • Like
Likes   Reactions: TheDemx27
Chestermiller said:
This result is right on target, and is the way I would have solved the problem too. Nice job.

Thanks for checking me.
 

Similar threads

Replies
44
Views
4K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
7
Views
2K
Replies
7
Views
24K