How to Calculate Heat Needed to Convert Ice to Steam at Different Temperatures?

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Homework Help Overview

The discussion revolves around calculating the total heat required to convert 150g of ice at -10°C into steam at 110°C. Participants are exploring the relevant equations and values associated with specific heat, latent heat of fusion, and latent heat of vaporization.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are attempting to apply the equations for heat transfer, including Q = mcΔT and Q = mLf, but express uncertainty about their calculations. There are questions regarding the completeness of the approach and whether all necessary steps are included.

Discussion Status

Some participants are seeking clarification on their calculations and are encouraged to provide full details of their attempts. There is recognition that additional steps may be required to arrive at the correct answer, and participants are exploring the need to sum multiple values through various equations.

Contextual Notes

Participants note that the answer they believe to be correct is 109.5 kcal, indicating a potential misunderstanding of the problem's requirements or the calculations involved.

domyy
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Homework Statement



Calculate the amount of heat to be added to warm 150g of ice from -10celsius to produce steam at 110C?

Homework Equations



I believe some relevant equations would be :
Q= mcdeltat
Q= mlf

I also have some values as:

Cice= 0.5 Cal/gcelsius
Lf= 80 Cal/g

C water= 1.0 Cal/gC

Steam= 0.5cal/gC
Lv = 540cal/g

The Attempt at a Solution



My attempt is wrong. I just know the answer, but I want to learn how to get to it. Thank you all in advance!
 
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hi domyy! :wink:

show us your full calculations, and then we'll see what went wrong, and we'll know how to help! :smile:
 
What did is wrong. I tried something simple but there's probably more that I do not know.
I did:

Q = 150g . 0.5 Cal/gC. 100C = 7500

Also tried,

Q= mlf = 150g . 80 Cal/g = 12,000

But I know the answer is 109.5 kcal.
 
domyy said:
What did is wrong. I tried something simple but there's probably more that I do not know.
I did:

Q = 150g . 0.5 Cal/gC. 100C = 7500

Also tried,

Q= mlf = 150g . 80 Cal/g = 12,000

But I know the answer is 109.5 kcal.

sorry, i can't follow that

you seem to have left some things out

can you please write it out properly?
 
Q = 150g x 0.5cal/gC x 100C = 7500

C= Celsius

Q = mLf = 150g x 80 Cal/g = 12,000

But it's wrong. The answer is 109.5 kcal. I need to know the formulas or steps I am missing. The problem is more than that. I believe I am supposed to find several values through equations and sum them.
 

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