How to Calculate Inductance in an R-L Circuit?

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SUMMARY

The inductance (L) in a 50Hz AC circuit with a 12Ω resistor and 5Ω inductive reactance is calculated using the formula L = XL / (2πF). Substituting the values, L is determined to be 0.0159 H or 15.9 mH. The calculation process involves correctly applying the inductive reactance formula XL = 2πFL and ensuring proper mathematical notation. The final result confirms the inductance value is accurate based on the provided parameters.

PREREQUISITES
  • Understanding of inductive reactance and its formula (XL = 2πFL)
  • Basic knowledge of AC circuit analysis
  • Familiarity with the concept of series circuits
  • Proficiency in using scientific calculators for electrical calculations
NEXT STEPS
  • Study the relationship between inductance and frequency in AC circuits
  • Learn about the impact of resistance on circuit behavior
  • Explore different methods for calculating inductance in various circuit configurations
  • Investigate the use of simulation tools for circuit analysis, such as LTspice or Multisim
USEFUL FOR

Electrical engineering students, circuit designers, and professionals involved in AC circuit analysis and inductance calculations will benefit from this discussion.

Ryanyates1988
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Homework Statement



Using circuit analysis calculate the inductance (L) within an electrical 50hz AC circuit containing a 12Ω resistor and inductive reactance of 5Ω which are in series.

Homework Equations



Inductive reactance:
XL = 2∏FL

Therefore inductance:
L = XL\2∏F

The Attempt at a Solution



Using my calculator I achieve the following:

L = (XL)\(2)(∏)(F)
L = 5Ω \ (2∏) x (50)
L = 5Ω \ 314.159
L = 0.0159 H
L = 15.9mH

I believe this value is correct.
 
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Ryanyates1988 said:
Using circuit analysis calculate the inductance (L) within an electrical 50hz AC circuit containing a 12Ω resistor and inductive reactance of 5Ω which are in series.


Homework Equations



Inductive reactance:
XL = 2∏FL

Therefore inductance:
L = XL\2∏F
Hi Ryanyates1988. http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

Your "\" is not a recognized engineering maths symbol. Regardless of what your calculator may use, you must express maths statements correctly in all other contexts, and include the necessary parentheses.

Using my calculator I achieve the following:

L = (XL)\(2)(∏)(F)
L = 5Ω \ (2∏) x (50)
L = 5Ω \ 314.159
L = 0.0159 H
L = 15.9mH
I believe this value is correct. ✔ [/size][/color]
 
Last edited by a moderator:
Hi Nascent,

Thank you for your reply. I will look up the symbols and post on my next questions.

Thanks!
 

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