Engineering How to Calculate Inductance in an R-L Circuit?

AI Thread Summary
To calculate the inductance (L) in a 50Hz AC circuit with a 12Ω resistor and 5Ω inductive reactance in series, the formula L = XL/(2πF) is used. Substituting the values, L is calculated as 5Ω divided by 314.159, resulting in 0.0159 H or 15.9 mH. The calculation is confirmed as correct. The discussion also highlights the importance of using proper mathematical symbols in engineering contexts. Overall, accurate calculations and proper notation are essential for clarity in circuit analysis.
Ryanyates1988
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Homework Statement



Using circuit analysis calculate the inductance (L) within an electrical 50hz AC circuit containing a 12Ω resistor and inductive reactance of 5Ω which are in series.

Homework Equations



Inductive reactance:
XL = 2∏FL

Therefore inductance:
L = XL\2∏F

The Attempt at a Solution



Using my calculator I achieve the following:

L = (XL)\(2)(∏)(F)
L = 5Ω \ (2∏) x (50)
L = 5Ω \ 314.159
L = 0.0159 H
L = 15.9mH

I believe this value is correct.
 
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Ryanyates1988 said:
Using circuit analysis calculate the inductance (L) within an electrical 50hz AC circuit containing a 12Ω resistor and inductive reactance of 5Ω which are in series.


Homework Equations



Inductive reactance:
XL = 2∏FL

Therefore inductance:
L = XL\2∏F
Hi Ryanyates1988. http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

Your "\" is not a recognized engineering maths symbol. Regardless of what your calculator may use, you must express maths statements correctly in all other contexts, and include the necessary parentheses.

Using my calculator I achieve the following:

L = (XL)\(2)(∏)(F)
L = 5Ω \ (2∏) x (50)
L = 5Ω \ 314.159
L = 0.0159 H
L = 15.9mH
I believe this value is correct. ✔ [/size][/color]
 
Last edited by a moderator:
Hi Nascent,

Thank you for your reply. I will look up the symbols and post on my next questions.

Thanks!
 

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