- #1

- 8

- 0

Ʃ(2^n * x^n), n starts from 0 to infinity. How can I calculate this? Do I have to transform it into something else where I know the outcome of the Σ like we do with the geometric functions?

- Thread starter thecaptain90
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- #1

- 8

- 0

Ʃ(2^n * x^n), n starts from 0 to infinity. How can I calculate this? Do I have to transform it into something else where I know the outcome of the Σ like we do with the geometric functions?

- #2

- 798

- 34

Let X=2x

Ʃ(2^n * x^n), n starts from 0 to infinity. How can I calculate this? Do I have to transform it into something else where I know the outcome of the Σ like we do with the geometric functions?

Ʃ(X^n) is the classical geometric series.

- #3

- 8

- 0

Thanks, didn't think of doing this.

- #4

- 56

- 0

Be advised that |X| < 1 to treat this as a geometric series.

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