How to Calculate Moment of Inertia for a Disk Using Calculus?

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SUMMARY

The moment of inertia for a disk about the axis perpendicular to its plane is calculated using the formula I = 1/2 MR². The perpendicular axis theorem states that the moment of inertia about an axis in the plane of the disk is I = 1/4 MR². The discussion highlights the challenge of deriving the second result using calculus, particularly when integrating the mass of a disk section, leading to complex calculations. The user ultimately resolved their query independently.

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  • Understanding of moment of inertia concepts
  • Familiarity with calculus, specifically integration techniques
  • Knowledge of the perpendicular axis theorem
  • Basic physics principles related to rotational motion
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  • Study the derivation of moment of inertia for various shapes using calculus
  • Explore the application of the perpendicular axis theorem in different contexts
  • Learn about the integration of mass distributions in physics
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jeremy5561
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I know that the moment of inertia of a disk about the axis perpendicular to the plane of the disk is

I=1/2 MR^2

and by the perpendicular axis theorem the moment of inertia about the other axis is

I=1/4 MR^2

I want to get the 2nd result with calculus. I can't get the right answer. What am I doing wrong?

I know the moment of inertia of a rod is 1/12 MR^2
I take the mass of a section of the disc to me pyr dx where y is the depth of the disc
but when I integrate it gets really messy.

What's the correct way to do this?

http://individual.utoronto.ca/jeremyli/moi.jpg
 
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I got it

OH nevermind I got it.
 

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