How to Calculate Reflection Coefficient for Light at Air to Silver Interface?

[drcrabs]

How does one calculate the reflection coefficient for light at an air to silver interface at optical frequencies ($$\omega = {4 *10^{15} s^{-1}}$$)
given

$$\mu_{I} = \mu_{T} = \mu_{0} , \sigma = {6 * 10^7 mhom^{-1}}$$

 

[Meir Achuz]

The reflection is close to 100% for silver.
the reflected intensity is I_r=I_0-I_absorbed.
$I_{absorbed}=\sqrt{\omega/8\pi\sigma}I_0$ in Gaussian units.

 

[drcrabs]

Would this work?

Knowing the frequency means we can find the wavelength clearly, which has units metres, clearly. When combined with $$\sigma = {6 * 10^7 mhom^{-1}}$$ to get the impedance of the silver. Then taking the ratio with the impedance of free space and assuming normal incidence

$$r =\frac{1 - \beta}{1 + \beta}$$

where $$\beta = \frac{\eta_0}{\eta_s}$$

Would this work?

 

[Meir Achuz]

How would you calculate \eta?

 

[drcrabs]

eta_s is the impeance of silver. As indicated previously a value with ohm units can be achieved by combining wavelength with the value of conductivity. What I am asking is, is this a valid statement?

 

[Meir Achuz]

No. Units are not a calculation.

 

[luckysahi]

i want to know about the motion of the stelites totely

 

[luckysahi]

basic defination of electromagnatic physics