How to Calculate Reflection Coefficient for Light at Air to Silver Interface?

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    Electromagnetism
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Homework Help Overview

The discussion revolves around calculating the reflection coefficient for light at the air to silver interface, particularly at optical frequencies. Participants are exploring the implications of given parameters such as permeability and conductivity in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between frequency, wavelength, and impedance in calculating the reflection coefficient. There are attempts to derive formulas and clarify the validity of statements regarding impedance and conductivity.

Discussion Status

The discussion is active, with participants questioning the validity of certain statements and exploring different approaches to calculating the reflection coefficient. Some guidance has been offered regarding the relationship between impedance and the parameters provided, but there is no explicit consensus on the methods discussed.

Contextual Notes

There are indications of confusion regarding units and calculations, with some participants questioning the validity of certain approaches based on dimensional analysis. Additionally, unrelated posts indicate a potential divergence in focus within the thread.

drcrabs
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How does one calculate the reflection coefficient for light at an air to silver interface at optical frequencies (\omega = {4 *10^{15} s^{-1}})
given

\mu_{I} = \mu_{T} = \mu_{0} , \sigma = {6 * 10^7 mhom^{-1}}
 
Last edited:
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The reflection is close to 100% for silver.
the reflected intensity is I_r=I_0-I_absorbed.
I_{absorbed}=\sqrt{\omega/8\pi\sigma}I_0 in Gaussian units.
 
Would this work?

Knowing the frequency means we can find the wavelength clearly, which has units metres, clearly. When combined with \sigma = {6 * 10^7 mhom^{-1}} to get the impedance of the silver. Then taking the ratio with the impedance of free space and assuming normal incidence

r =\frac{1 - \beta}{1 + \beta}

where \beta = \frac{\eta_0}{\eta_s}

Would this work?
 
Last edited:
How would you calculate \eta?
 
eta_s is the impeance of silver. As indicated previously a value with ohm units can be achieved by combining wavelength with the value of conductivity. What I am asking is, is this a valid statement?
 
No. Units are not a calculation.
 
i want to know about the motion of the stelites totely
 
basic defination of electromagnatic physics
 

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