How to Calculate Reflection Coefficient for Light at Air to Silver Interface?

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SUMMARY

The calculation of the reflection coefficient for light at the air to silver interface involves understanding the impedance of silver and free space. The reflection coefficient, denoted as r, is calculated using the formula r = (1 - β) / (1 + β), where β = η₀ / ηₛ. Given the conductivity σ = 6 * 10^7 mhom⁻¹ and the optical frequency ω = 4 * 10¹⁵ s⁻¹, the absorbed intensity can be expressed as Iₐₛₛₒᵣbₑd = √(ω / 8πσ) I₀. The discussion confirms that the approach to calculating the reflection coefficient is valid, provided the correct units and relationships are maintained.

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How does one calculate the reflection coefficient for light at an air to silver interface at optical frequencies (\omega = {4 *10^{15} s^{-1}})
given

\mu_{I} = \mu_{T} = \mu_{0} , \sigma = {6 * 10^7 mhom^{-1}}
 
Last edited:
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The reflection is close to 100% for silver.
the reflected intensity is I_r=I_0-I_absorbed.
I_{absorbed}=\sqrt{\omega/8\pi\sigma}I_0 in Gaussian units.
 
Would this work?

Knowing the frequency means we can find the wavelength clearly, which has units metres, clearly. When combined with \sigma = {6 * 10^7 mhom^{-1}} to get the impedance of the silver. Then taking the ratio with the impedance of free space and assuming normal incidence

r =\frac{1 - \beta}{1 + \beta}

where \beta = \frac{\eta_0}{\eta_s}

Would this work?
 
Last edited:
How would you calculate \eta?
 
eta_s is the impeance of silver. As indicated previously a value with ohm units can be achieved by combining wavelength with the value of conductivity. What I am asking is, is this a valid statement?
 
No. Units are not a calculation.
 
i want to know about the motion of the stelites totely
 
basic defination of electromagnatic physics
 

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