How to calculate resistance and voltage using a multimeter

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To calculate resistance and voltage using a multimeter, first ensure the power supply is disconnected when measuring resistance across R1 and R2. For measuring input voltage (Vin), connect the multimeter across the power supply terminals while the circuit is closed for accurate readings. To measure the current through R2, connect an ammeter in series with the circuit. It's suggested that calculating R1 and R2 may involve measuring voltages and currents rather than direct resistance measurements. Understanding voltage division and current division rules is essential for accurate calculations in the lab setup.
jumbogala
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Homework Statement


This is just something I want to know, so it doesn't really have a problem statement.

But I'm doing a lab tomorrow that uses voltage dividers. So it's two resistors R1 and R2 in series with a power supply. The power supplies Vin (the input voltage). A voltmeter is connected across R2 to measure Vout.

The lab also asks me to measure the values of R1 and R2, as well as the current going through R2. I want to make sure I know how to measure each of these properly.

Homework Equations





The Attempt at a Solution


R1 and R2: connect the multimeter with the power supply disconnected, across the resistors and measure?

Vin would just be the amount of voltage supplied by the power supply, correct? I guess I just hook up the multimeter across the terminals of the power supply...

Current across R2: Can't I just connect an ammeter in series with the circuit anywhere and take the reading? Can you measure current with a multimeter (I've never used one). Thanks!
 
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jumbogala said:
R1 and R2: connect the multimeter with the power supply disconnected, across the resistors and measure?

Vin would just be the amount of voltage supplied by the power supply, correct? I guess I just hook up the multimeter across the terminals of the power supply...

Current across R2: Can't I just connect an ammeter in series with the circuit anywhere and take the reading? Can you measure current with a multimeter (I've never used one). Thanks!

All of the above is correct, but to get a more accurate reading on Vin you should measure the voltage while the circuit is closed. The power supply's internal resistance is going to lower the voltage by a non-negligible amount.

I have a suspicion that the teacher wanted you to calculate R1 and R2 by measuring voltages and currents instead of measuring resistance directly. In that case, would you know how to get R1 and R2?
 
In case this helps, the voltage division and current division rules are:

When a voltage V is divided across two series resistors, the voltage divides in the same proportions as each resistor.
voltage across R1 = V [R1/(R1+R2)]
voltage across R2 = V [R2/(R1+R2)]

However, when a current I divides between two parallel resistors, the current in each resistor divides in proportion with the OTHER resistor:
current through R1 = I [R2/(R1+R2)]
current through R2 = I [R1/(R1+R2)]
 
What does "measure the voltage while the circuit is closed" mean? (Can you tell I'm new at this? haha) And yep, I could find R1 and R2 theoretically if I needed to.

And thank you mike, that does help =)
 
jumbogala said:
What does "measure the voltage while the circuit is closed" mean?
Measure the voltage when you have R1 and R2 connected to the power supply.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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