How to calculate resistance between two electrodes filled with water

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Discussion Overview

The discussion centers on calculating the electrical resistance between two electrodes filled with water, specifically under two experimental conditions: one involving rectangular plates and the other involving cylindrical geometry. The conductivity of the water solution is provided as a known parameter.

Discussion Character

  • Technical explanation, Homework-related, Mathematical reasoning

Main Points Raised

  • One participant asks for help in calculating resistance between two electrodes in water with known conductivity, describing two specific geometries: rectangular plates and cylindrical electrodes.
  • Another participant provides a formula for resistance in the rectangular case, indicating the relationship between resistivity, length, and cross-sectional area.
  • A further response suggests that a similar approach can be taken for the cylindrical geometry, mentioning the need for integration over small volume elements.
  • One participant shares a link to a Wikipedia page on resistivity, potentially for additional reference.
  • A participant inquires about how to substitute the known conductivity value into the resistivity formula, seeking clarification on the relationship between conductivity and resistivity.
  • Another participant notes that conductivity and resistivity are likely inverses, advising to check the units for confirmation.

Areas of Agreement / Disagreement

Participants have not reached a consensus on the calculation methods, and there are multiple viewpoints regarding the application of formulas and the relationship between conductivity and resistivity.

Contextual Notes

The discussion does not resolve the specific mathematical steps required for the cylindrical case, nor does it clarify the exact relationship between conductivity and resistivity in this context.

guptasuryakant
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Hello ,

Can someone from this group help me ,how to calculate resistance between two electrodes filled with water with a known conductivity solution.

In my case I have two experimental conditions. First there are two rectangular plates separated with a gap of 30 mm.

In second case this is a cylindrical geometry Innner electrode dia is 10 mm. And outer electrode dia is 50 mm. In between water is filled with a conductivity of 500µ cm/cm.

If some one can answer atleast for one case it will be useful for me.

regards
 
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For the rectangular case, the resistance is

[tex]R = \frac{\rho L}{A}[/tex]

Where A is the crossectional area, and the resistivity is [tex]\rho[/tex]

The calculation is similar for the cylindrical geometry, but you need to set up an integral to do it over small volume elements that approximate the rectangular situation.
 
How I can put the value in place of resistivity

Thanks for your prompt reply

How I can put the value in place of resistivity in above fourmula
 
You said you knew the conductivity of the solution. Probably conductivity and resistivity are just inverses, but check the units to be sure.
 

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