How to calculate rollover based on angle of turn, velocity, and wheel distance

yw917
Messages
2
Reaction score
0
This is for my senior design project for which we are constructing a luggage propulsion system.

One of the things I have to do is calculate what is the sharpest turn possible for a given speed with a given wheel distance without it rolling over. I do not have the actual numbers yet as we are trying to decide on an optimal wheel distance. I guess what I am looking for are the formulas you would use to calculate such things and maybe an example.

The dimensions of our product are 18''w x 12'' l x 30''h, for the purpose of calculations we are assuming the center of gravity is right in the middle even though in actuality it is not.

Thanks.
 
Physics news on Phys.org
Please post your own attempt.
 
This isn't a homework problem, I took physics 1 four years ago and don't remember much, don't have a textbook either.

I'm trying to get pointed in the right direction like which formulas you would use to calculate such a thing.

I understand the concept of needing the center of gravity to be supported but what I don't know is how to calculate if you turn at a certain angle at a certain speed how far the device will be tilted.
 
You start by drawing a 'free body diagram'. This takes one rigid component of the system (the vehicle) and marks all the forces on it with arrows. These should show the approximate direction of the force, a label (like 'N' for the directly upward force from the road), and the line through which the force acts (gravity acts through the centre of gravity). Where friction is involved, it's usual to separate the normal force (the one perpendicular to the surfaces) from the frictional force (parallel to the surfaces). Since the vehicle is not skidding, the friction will be static friction.
Next, you consider the acceleration which the vehicle undergoes. Generally this will involve both linear and rotational acceleration. Since forces are vectors, it helps to consider linear forces in two or three directions separately. This is called 'resolving'. In the present case, horizontal and vertical. (If the surface is banked, it might be better to resolve parallel and perpendicular to the surface.) For the rotation, you need to pick a point to take moments about.
You should get three equations, something like:
- resultant acceleration vertically * mass = net upwards force
- resultant acceleration horizontally * mass = net sideways force
- resultant angular acceleration * moment of inertia = net torque
For your problem, the first and third of those should equate to zero. The middle one is nonzero: the centripetal acceleration required to negotiate the bend = v2/r.
There's plenty of stuff on the net which you can follow up from those pointers. Forgive me for not taking the time to provide a complete introductory course on dynamics.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
14
Views
867
Replies
9
Views
2K
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 24 ·
Replies
24
Views
4K
Replies
3
Views
2K
Replies
1
Views
2K
Replies
9
Views
2K
Replies
25
Views
2K
Replies
31
Views
2K