How to Calculate the Angle in a Cone with Given Height and Circumference?

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To calculate the angle alpha in a cone with a height that is one-third of the circumference of the base, the relationship h = (1/3) * 2 * Pi * r is established. The problem involves using trigonometry with a right triangle where the base opposite angle alpha is equal to r and the adjacent side is (2 * Pi * r) / 3. There is a request for clarification on how to derive the adjacent side and whether there is a predefined formula for the hypotenuse. The discussion highlights the confusion around the definitions and relationships in the problem, with participants acknowledging the learning curve involved. Overall, the conversation emphasizes the application of trigonometric principles to solve for the angle in a cone.
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Homework Statement


The height h of the cone is 1/3 of l the circumference of the base .

Homework Equations


Calculate the angle alpha. Give your answer with 2 decimals.

The Attempt at a Solution


h=1/3 * 2*Pi*r

and then we don't have the radius
 

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you do have r, r=r. you have a right triangle with base opposite side equal to r and an adjacent side = 2pi*r/3. apply some trigonometry and you should be able to find alpha
 


I'm curious about how you're able to get an exact answer to this problem even though it's given in general terms. I hope someone could shed some light on this.
 


armolinasf said:
you do have r, r=r. you have a right triangle with base opposite side equal to r and an adjacent side = 2pi*r/3. apply some trigonometry and you should be able to find alpha

where did that ''adjacent side = 2pi*r/3'' came from :bugeye:
 


If you make a a right triangle with right angle at the base and angle alpha as the vertex. The side adjacent to angle alpha is the height of the cone which is defined as h=(2*pi*r)/3
 


i have to say this is new for me..can you please demostrate how to got it?
also if there is a pre-defined formula for the hypotenuese i would be glad to know it
 


chawki said:
i have to say this is new for me..can you please demostrate how to got it?
also if there is a pre-defined formula for the hypotenuese i would be glad to know it

OH my lord..i just asked to demostrate that and forgot that it was given :rolleyes: i should go to sleep :frown:
 


Haha...we've all been there at some point, it'll probably do a world of good to get some sleep
 

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