How to Calculate the Area of a Square Using Definite Integrals?

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Homework Help Overview

The discussion revolves around calculating the area of a square using a definite integral. The original poster mentions a specific integral involving the function 0.43890022x over the interval from 1 to 10, seeking assistance in understanding the problem.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the area of a square and the result of the definite integral. There are attempts to clarify the definition of a square and the concept of definite integrals. Some participants question the original poster's understanding of calculus and suggest that basic knowledge is necessary for solving the problem.

Discussion Status

The discussion includes various interpretations of the problem and attempts to provide guidance on how to approach the integral. While some participants offer insights into the calculations, there is no explicit consensus on the best way to proceed. The original poster expresses gratitude for the help received, indicating a positive engagement with the responses.

Contextual Notes

The original poster indicates a lack of familiarity with calculus, which may impact their ability to engage with the problem fully. There is a mention of a personal motivation related to a friend's website, adding a layer of urgency to the request for help.

merven
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THE AREA OF A SQUARE WITH SIDE LENGTHS EQUAL TO THE DEFINITE INTEGRAL OF (0.43890022*X) FROM 1 TO 10


please help me...

Merven
 
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You need to show your work before you get help. What have you done with this question?
 
ok well i posted it in the calculus forums but no one helped...
my friend is making a new website and he told me the only way i could get a peak is by solving this equation, and the reason he did this is becasue he knows far to well i can't do math, I recenty graduated HS and know nothing of calculus, that's why I am askign here, if someone would be willing to help me or to even give me crash corse because they don't think its right to just give me the answer i would be more then willing to try and learn...
thanks
Merven
 
lol; most odd thing i have ever heard ...
but, if your story is true, i shall try and help.

I take it you would know that a square has equal length sides?
hence the area of the square is equal to the length by width (or in this case l^2:
A(square) = l^2
(if u really need: http://en.wikipedia.org/wiki/Square_(geometry))

In regard to the next section, i doubt it will be even the slightest bit understandable, but none-the-less ...
A definite integral basically finds the area underneath a graph in a set region i.e. between a and b: http://en.wikipedia.org/wiki/Image:Integral_as_region_under_curve.svg
where f(x) is your function, such that: f(x) = 0.43890022x
but for our purposes, we just want to find the numerical answer for this integral as a means of determining the area of the square.

The definite integral notation for this is:
\int_{1}^{10} {0.43890022x}
This ican be explained as; the definite integral between 1 and 10 for the equation 0.43890022 as required.

Now we can simplify this integral and obtain a numerical answer:
\int_{1}^{10} {0.43890022x}
= 0.43890022 \int_{1}^{10} {x} (taken out factor)
= 0.43890022(\frac {x^2}{2}) between 1 and 10
= 0.43890022 ((\frac {10^2}{2}) - (\frac {1^2}{2}))
plug that into your calculator and you get:
21.72556089

remember from before:
A(square) = l^2
therefore:
A(square) = 21.72556089^2
=471.999996

wow that took longer than I thought, but yeh, hope this helps your cause.
You must understand that you cannot learn how to do definite integration with no understanding of basic calculus methods etc; for the parts you don't understand, just take them as facts ...
Steven
 
Last edited:
Assuming of course that the variable of integration is X and that X varies from 1 to 10 ...
 
hehe, yer ...

in respect to the problem given; could it be anything else??
or is that just complicating things more?
lol

Steven
 
lol, nah it had to be X, I was just pointing out ways for the OP to get back at his supercilious friend :biggrin:
 
haha, yeh good point and idea ...
pretty nasty form of entrance don't you think?
 
As long as you know what 'integral means' calculus is completely irrelevant to the question. It's just a straight line graph - you can find the area by elementary means.
 
  • #10
omg if that trully is the answer, i got it right when i used one fo the calculators. but double guessed and threw it out since i had no clue. lol wow steven10137 you are my hero... lol now i have to see what he says, ill come back and post his reply :) thanks a million guys
Merven
 
  • #11
merven said:
omg if that trully is the answer, i got it right when i used one fo the calculators. but double guessed and threw it out since i had no clue. lol wow steven10137 you are my hero... lol now i have to see what he says, ill come back and post his reply :) thanks a million guys
Merven

not at all
:)
 
  • #12
lol its awsome ty again, he was shocked but gave in after i got angry LOL, thank you all again
 

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