lol; most odd thing i have ever heard ...
but, if your story is true, i shall try and help.
I take it you would know that a square has equal length sides?
hence the area of the square is equal to the length by width (or in this case [tex]l^2[/tex]:
[tex]A(square) = l^2[/tex]
(if u really need:
http://en.wikipedia.org/wiki/Square_(geometry))
In regard to the next section, i doubt it will be even the slightest bit understandable, but none-the-less ...
A definite integral basically finds the area underneath a graph in a set region i.e. between a and b:
http://en.wikipedia.org/wiki/Image:Integral_as_region_under_curve.svg
where f(x) is your function, such that: [tex]f(x) = 0.43890022x[/tex]
but for our purposes, we just want to find the numerical answer for this integral as a means of determining the area of the square.
The definite integral notation for this is:
[tex]\int_{1}^{10} {0.43890022x}[/tex]
This ican be explained as; the definite integral between 1 and 10 for the equation 0.43890022 as required.
Now we can simplify this integral and obtain a numerical answer:
[tex]\int_{1}^{10} {0.43890022x}[/tex]
[tex]= 0.43890022 \int_{1}^{10} {x}[/tex] (taken out factor)
[tex]= 0.43890022(\frac {x^2}{2})[/tex] between 1 and 10
[tex]= 0.43890022 ((\frac {10^2}{2}) - (\frac {1^2}{2}))[/tex]
plug that into your calculator and you get:
[tex]21.72556089[/tex]
remember from before:
[tex]A(square) = l^2[/tex]
therefore:
[tex]A(square) = 21.72556089^2[/tex]
[tex]=471.999996[/tex]
wow that took longer than I thought, but yeh, hope this helps your cause.
You must understand that you cannot learn how to do definite integration with no understanding of basic calculus methods etc; for the parts you don't understand, just take them as facts ...
Steven