How to calculate the band structure?

Click For Summary
To calculate the band structure, one must define points at the edges of the first Brillouin zone, typically including vertices, centers of edges, or centers of faces. The specific coordinates for these points, such as \Gamma, X, K, and W, vary depending on the Brillouin zone being analyzed, and resources are available online to look them up. The number of points between these coordinates is generally chosen based on the distance between them, often in a somewhat arbitrary manner. High symmetry points are crucial for the calculation, and users are advised to consult tables for these points specific to their crystal structure. Understanding these concepts is essential for accurate band structure calculations.
Miranda_Lucy
Messages
2
Reaction score
0
Hi, all,
I want to calculate the band structure and there is example such like that:

BandLinesScale pi/a
%block BandLines # These are comments

1 0.000 0.000 0.000 \Gamma # Begin at Gamma
50 2.000 0.000 0.000 X # 25 points from Gamma to X
20 2.000 1.000 0.000 W # 10 points from X to W
30 1.000 1.000 1.000 L # 15 points from W to L

40 0.000 0.000 0.000 \Gamma # 20 points from L to Gamma
50 1.500 1.500 0.000 K # 25 points from Gamma to K
20 1.000 1.000 1.000 L # 15 points from W to L
30 2.000 0.500 0.500 W # 10 points from L to U

20 2.000 0.000 0.000 X # 25 points from U to X
Is there anyone can tell me how to define the number of the points and the coordinate of these points? thank you very much

Yours,
Lucy
 
Physics news on Phys.org
The coordinates are points at the edge of the first Brillouin zone (except for gamma). If you imagine the 3D Brillouin zone, the points will be either vertices, centers of edges, or centers of faces. You generally have to look those up, as the notation and location of these points depends on your Brillouin zone.

For the number of points, it's a somewhat-arbitrarily assigned number. Usually you would choose the number of points in proportion to the distance between the special coordinates that line segment connects.
 
kanato said:
The coordinates are points at the edge of the first Brillouin zone (except for gamma). If you imagine the 3D Brillouin zone, the points will be either vertices, centers of edges, or centers of faces. You generally have to look those up, as the notation and location of these points depends on your Brillouin zone.

For the number of points, it's a somewhat-arbitrarily assigned number. Usually you would choose the number of points in proportion to the distance between the special coordinates that line segment connects.

Hi,thank you very much. but I am still confused about the coordinate.
Can you give me an example? Someone said we should choose the symmetry points---special K point. How can we find the highly symmetry point.
Thank you very much
Yours,
Lucy
 
Well, I already said that high symmetry points are either vertices, centers of edges, or centers of faces of the Brillouin zone. If you want the names (X, K, M, etc.) you have to look them up for your particular Brillouin zone, and for some BZ's they will depend on things like the c/a ratio.

Look at the Brillouin zone for fcc here:
http://en.wikipedia.org/wiki/Brillouin_zone
X is a center of a square face, K and U are centers of an edges, W is a vertex and L is the center of a hexagonal face.
 
Lucy,

Try to google “table for high symmetry points for brillouin zone” and you should get several web sites that contains table for the coordinates of the high symmetry points for several types of crystals.

Rany
 
Thread 'Unexpected irregular reflection signal from a high-finesse cavity'
I am observing an irregular, aperiodic noise pattern in the reflection signal of a high-finesse optical cavity (finesse ≈ 20,000). The cavity is normally operated using a standard Pound–Drever–Hall (PDH) locking configuration, where an EOM provides phase modulation. The signals shown in the attached figures were recorded with the modulation turned off. Under these conditions, when scanning the laser frequency across a cavity resonance, I expected to observe a simple reflection dip. Instead...

Similar threads

  • · Replies 3 ·
Replies
3
Views
4K
Replies
2
Views
4K
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
11K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
3
Views
8K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
3
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K