How to calculate the energy of the ice absorbs heat then becomes water

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SUMMARY

The discussion focuses on calculating the energy required for ice at 0°C to melt into water at the same temperature. The key equation to use is the latent heat of fusion, which is 334 J/g or 80 cal/g for ice. The specific heat capacities of ice and water are not relevant in this scenario since the temperature remains constant during the phase change. Thus, the energy absorbed by the ice can be calculated using the formula Q = m * L, where L is the latent heat of fusion.

PREREQUISITES
  • Understanding of latent heat and phase changes
  • Familiarity with the concept of specific heat capacity
  • Basic knowledge of thermodynamics
  • Ability to perform unit conversions between calories and joules
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  • Study the concept of latent heat in detail, focusing on phase transitions
  • Learn how to calculate energy changes using Q = m * L for different substances
  • Explore the differences in specific heat capacities between various materials
  • Investigate real-world applications of latent heat in climate science and engineering
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Students in physics or chemistry, educators teaching thermodynamics, and anyone interested in understanding energy transfer during phase changes.

destroying
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as the topic asks
but, if i want to know the energy of the 0 Centigrade melt into 0 Centigrade water, how to calculate it?
i mean i don't know how to use the equation Q=c*m*t, 'cause the specific heat of water and that of ice are different
 
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The equation q=msd(theta) would give zero anyway because d(theta) is zero, it is not to be used.
There's a fixed quantity, the latent heat, which is taken as 80cal/g or 334J/g for fusion of ice
 
got it, thanks
 

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