How to calculate the leak rate based on pressure drop

Click For Summary
SUMMARY

The discussion focuses on calculating the leak rate and fluid loss from pressurized vessels filled with water over a 30-minute period. The intern is utilizing Boyle's Law, specifically the equation P1 * V1 = P2 * V2, to derive the relationship between pressure drop and volume change. However, the intern encounters challenges with this method and seeks clarification on the viability of using hydrostatic pressure calculations, specifically WH = P/(rho * g), to determine fluid loss. The conversation highlights the importance of understanding the pressure drop versus flow rate relationship and the characteristics of potential cracks in the vessel.

PREREQUISITES
  • Understanding of Boyle's Law and its application in fluid dynamics
  • Knowledge of hydrostatic pressure calculations
  • Familiarity with fluid mechanics concepts, particularly related to leak detection
  • Basic principles of pressure vessel design and inspection
NEXT STEPS
  • Research the relationship between pressure drop and flow rate in fluid systems
  • Study hydrostatic testing methods for pressure vessels
  • Learn about the impact of crack size and location on leak rates
  • Explore advanced fluid dynamics simulations for leak detection
USEFUL FOR

Engineers, interns in mechanical or chemical engineering, and professionals involved in pressure vessel design and maintenance will benefit from this discussion.

blinkz303
Messages
2
Reaction score
0
TL;DR
I am currently working on a project trying to calculate leak rates from pressurised vessels filled with water.
I am currently working on a project trying to calculate leak rate and fluid loss from pressurised vessels filled with water over a time period of 30 minutes. So far I have used the Boyles Law which assumes that PV/T = constant which gets us P1 * V1 = P2 * V2 and PdV+VdP = 0 I formed this over to PdV=VdP. and divided by the change in time to get dV/dt = - VdP/Pdt

Could anyone help me and tell me if I am on the right track here or have I overlooked something.
 
Engineering news on Phys.org
Is it liquid water or water vapor or are both present in the vessel. You need to establish the pressure drop vs flow rate relationship for the valve.
 
To clarify further: I am an intern at a company and I have been tasked with finding a method to calculate the leak rate and amount of fluid lost through possible cracks in a vessel. It can be assumed that the vessel is completely filled with water. I know the volume of the vessel and can figure out the hydrostatic pressure at the bottom of the vessel based on the volume. I have tried calculating the volume loss by calculating the change in the height of the water WH=P/rho*g
P being Pressure, rho being the density of water, g being the acceleration due to gravity.
I know the volume of water per meter of height and can therefore calculate the amount of water lost.
Would this be a viable method? I realized I am running into way to many problems using Boyle's law.
 
blinkz303 said:
To clarify further: I am an intern at a company and I have been tasked with finding a method to calculate the leak rate and amount of fluid lost through possible cracks in a vessel. It can be assumed that the vessel is completely filled with water. I know the volume of the vessel and can figure out the hydrostatic pressure at the bottom of the vessel based on the volume. I have tried calculating the volume loss by calculating the change in the height of the water WH=P/rho*g
P being Pressure, rho being the density of water, g being the acceleration due to gravity.
I know the volume of water per meter of height and can therefore calculate the amount of water lost.
Would this be a viable method? I realized I am running into way to many problems using Boyle's law.
Is there head space above the liquid water in the vessel? If so, what is in the head space, pure water vapor? Are the cracks exclusively on the bottom of the vessel, or are there cracks along the sides as well? how thick is the wall, and what are the approximate lengths of the cracks. Do you have any idea what the size of the crack openings are?
 

Similar threads

Replies
5
Views
4K
Replies
13
Views
3K
  • · Replies 29 ·
Replies
29
Views
9K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
6
Views
5K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 6 ·
Replies
6
Views
521
  • · Replies 10 ·
Replies
10
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K