How to Calculate the Specific Heat Capacity of an Unknown Metal

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SUMMARY

The specific heat capacity of an unknown metal can be calculated using the formula c = ΔE / (m * ΔT), where ΔE represents the heat gained by water. In this discussion, a metal with a mass of 50g at 200°C was placed in 125g of water, resulting in a temperature increase from 20°C to 28.35°C. The heat gained by the water was calculated as 4445.5 Joules, leading to a specific heat capacity of approximately 4.3 J/g°C for the metal. The principle that heat lost by the metal equals heat gained by the water is crucial for this calculation.

PREREQUISITES
  • Understanding of specific heat capacity concepts
  • Familiarity with the formula ΔE = m * ΔT * c
  • Basic knowledge of calorimetry
  • Ability to perform dimensional analysis
NEXT STEPS
  • Research the specific heat capacities of common metals for comparison
  • Learn about calorimetry techniques and their applications
  • Explore the concept of heat transfer and thermodynamics
  • Study the implications of heat loss and gain in different materials
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Students in physics or chemistry courses, educators teaching thermodynamics, and anyone interested in experimental methods for determining material properties.

Verbally
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Homework Statement




How can you calculate the specific heat capacity of an unknown metal? In my question the metal with a mass of 50g and a temperature of 200 degrees celsius was placed in 125 g of water with an initial temperature of 20 degrees celsius. After the simulation and the metal was placed in the water, the temperature of the water rose from 20 to 28.35. How can I find the specific heat capacity of the unknown metal? Then we have to research what metal corresponds to the resulting heat capacity.

Homework Equations



I know you have to use the original equation of ΔE=m*ΔT*c and rearrange it to isolate "c", thus resulting in the equation of c=ΔE/m*ΔT. But how do you calculate ΔE?


The Attempt at a Solution



What I did first is try to find ΔE:

= m x (T2-T1)
= 125 x (28.35-20)
= 125 x 8.35
= 1043.75 Calories = 4445.5 Joules

Then you can substitute that into c=ΔE/m*ΔT

c = 4445.5J / 125 x 8.35
= 4445.5 / 1043.75
= 4.3

I know I went wrong somewhere, could someone please explain to me where I did? I've been stuggling on this question forever!

Thanks.
 
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Heat lost by metal equals heat gained by water.
 
Borek said:
Heat lost by metal equals heat gained by water.

Ok, but how do you find the heat gained by water?
 
You could find the heat change in the water by reasoning from the definition that 1 calorie raises 1 g of water by 1 degree Celsius. That and the data you have let you get the answer through dimensional analysis.

If you want to be more mechanical (and, arguably, more efficient), you also have an equation that relates the change of temperature, mass, specific heat and change of heat content.

Do you see it?
 
Verbally said:
Ok, but how do you find the heat gained by water?

From the same m*ΔT*c - just for water.
 

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