How to Calculate Voltage Gain for Amplifiers B and D with Limited Input Voltage

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Homework Help Overview

The discussion revolves around calculating the voltage gain for amplifiers B and D based on provided characteristics and input voltage limitations. Participants are analyzing a graph that depicts the output voltage behavior of these amplifiers in response to a limited input voltage range of + & - 600mV.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss using the rise over run method to determine voltage gain, with some attempting to calculate specific values based on the graph. There are questions regarding the accuracy of the output voltage readings and the interpretation of the graph's details.

Discussion Status

Some participants have offered guidance on the approach to take for calculating voltage gain, while others express uncertainty about the graph's clarity and the potential for errors in the book's figures. Multiple interpretations of the output voltage values are being explored.

Contextual Notes

There is mention of a tutor's assistance and a specific allowance for a range in graph style questions on an exam, which may affect how participants approach the problem. The clarity of the graph is noted as a potential constraint in deriving accurate values.

breeno
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Homework Statement



"The graph shows the characteristics of four different voltage amplifiers (A-D). The input voltage to these amplifiers is limited to between + & - 600mV.

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If you cannot see it properly it also says "If the input voltage is as shown (see bottom graph), sketch the output voltage for amplifiers B and D."

Homework Equations



Voltage gain = change in output voltage divided by change in input voltage.



The Attempt at a Solution



To use B as an example. I've tried finding the voltage gain (rise over run or the formula above) to get 8.33. I then use that as the voltage gain and rearrange the above formula but alas it didn't work. If it helps, the book shows (for B) a peak voltage of 1.8v and a trough of 1.8v.

Any help would be appreciated.
 
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breeno said:
To use B as an example. I've tried finding the voltage gain (rise over run or the formula above) to get 8.33. I then use that as the voltage gain and rearrange the above formula but alas it didn't work. If it helps, the book shows (for B) a peak voltage of 1.8v and a trough of 1.8v.

For B, your rise over the run approach is the way to go. :approve: But you might want to redo the math. :frown: The way I see the figure (which isn't too easy, it's kind of squashed), the output voltages seems to around 5.0 V for an input voltage of around 0.55 V. That doesn't give a gain of 8.33.
 
collinsmark said:
For B, your rise over the run approach is the way to go. :approve: But you might want to redo the math. :frown: The way I see the figure (which isn't too easy, it's kind of squashed), the output voltages seems to around 5.0 V for an input voltage of around 0.55 V. That doesn't give a gain of 8.33.

It's 5v and 0.6v. :p

5/0.6 = 8.33.
 
breeno said:
It's 5v and 0.6v. :p

5/0.6 = 8.33.

Yeah, it's kind of hard for me to see because the figure is squished up. On the other hand, if you use 5/0.55 = 9.09, you'll get the answer in the book. I'm not sure if the book made a mistake in the figure, or the answer, or if it's just because I just can't interpret the figure very well myself.
 
collinsmark said:
Yeah, it's kind of hard for me to see because the figure is squished up. On the other hand, if you use 5/0.55 = 9.09, you'll get the answer in the book. I'm not sure if the book made a mistake in the figure, or the answer, or if it's just because I just can't interpret the figure very well myself.

Thanks for your help.

I went through with a tutor today and it turns out my system was right in the way of getting it and on an exam I will get a 10% range for graph style questions. I re-drew the graph on graph paper and ended up getting the correct answer.

Thanks for helping!
 

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