What is the power gain in dB for a voltage amplifier with a ratio of 200 between output voltage and input voltage?

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Discussion Overview

The discussion revolves around calculating the power gain in decibels (dB) for a voltage amplifier with a specified output to input voltage ratio of 200. Participants explore the relationship between voltage and power in this context and address a related subquestion regarding output voltage in dB.

Discussion Character

  • Technical explanation, Homework-related

Main Points Raised

  • One participant presents the problem of finding the power gain in dB given the voltage ratio Vo/Vi = 200.
  • Another participant explains that power is proportional to the square of voltage, under the assumption of equal resistances, and confirms that the solution provided is correct.
  • A third participant reiterates the relationship between power and voltage, affirming the correctness of the earlier explanation.
  • A participant expresses confusion regarding a subquestion about finding the output voltage when the input voltage is -6 dBV, questioning how Vo can equal 40 dB if it is 200 times larger than Vi.
  • Subsequently, the same participant retracts their question, indicating they have understood the solution.

Areas of Agreement / Disagreement

Participants generally agree on the relationship between voltage and power, but there is some confusion regarding the conversion of voltage levels to dB, particularly in the context of the subquestion.

Contextual Notes

The discussion does not resolve the confusion about the output voltage in dB, leaving the relationship between the input and output voltage levels in dB somewhat unclear.

MissP.25_5
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An amplitude of output voltage Vo of a voltage amplifier was compared to the amplitude of input voltage Vi. The ratio Vo/Vi was 200.

Find the power gain in dB.

Can someone explain to me how to find this? The solution is given as below, but I don't understand how can Po/Pi = 200^2
 

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Power goes as the square of voltage, assuming equal resistances: P = V^2/R.
The solution is correct.
 
rude man said:
Power goes as the square of voltage, assuming equal resistances: P = V^2/R.
The solution is correct.

Ah, I got it. There's another subquestion that I really don't understand. It says to find the output voltage when Vi is -6 dBV. I don't understand the solution. If Vo is 200 times larger than Vi, then how come Vo = 40 dB?
 

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Last edited:
Disregard my question. I have understood it :)
The solution seems to be written in a descending order.
 

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