How to convert units when calculating a dimensionless quantity?

Safinaz
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Homework Statement
For instance consider calculating this dimensionless quantity:

##
P= \frac{1}{H^4~~ (GeV)^4} \times \left(\frac{1}{k_0 ~~~(Mpc)^{-1}}\right)^{0.2} ~~(1)
##
Relevant Equations
Where H and k are constants. How to convert or choose units to make ##P## dimensionless.
where Mpc##^{-1} = 6.6 \times 10^{-39}## GeV.
The original quantity is given in this paper: [reference][1], equations: (31-33-34), where ##a(\eta)= \frac{1}{H\eta}##, so I considered in (1) only the constants which share by dimensions to ##P##.

Any help is appreciated!


[1]: https://arxiv.org/pdf/hep-th/0703290
 
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Safinaz said:
where Mpc##^{-1} = 6.6 \times 10^{-39}## GeV.
I am intereted in how do you get this relation ? Mpc has dimension of length L. GeV has dimensitn of energy ML^2T^-2.
 
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anuttarasammyak said:
I am intereted in how do you get this relation ? Mpc has dimension of length L. GeV has dimensitn of energy ML^2T^-2.
This is in a system of natural units where ##\hbar=c=1##.
 
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Likes Orodruin and anuttarasammyak
To add to that, in natural units length and time both have dimensions of inverse energy. It is incredibly common to use such units particularly in high-energy physics, relativity, and related fields.
 
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(30) and (31) seem to suggest that P(k) has same dimension with k^5. Is it OK? I have not found your (1) in the paper. Where is it ?
 
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