How to derive pv^gamma=constant

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SUMMARY

The discussion focuses on deriving the equation pVγ = constant for an ideal gas under reversible adiabatic conditions, where γ = Cp,m/Cv,m. Participants emphasize the importance of not assuming the equation being proven and highlight common mistakes in algebraic manipulation. The correct approach involves using the first law of thermodynamics to relate changes in internal energy and temperature to pressure and volume, ultimately leading to the desired relationship.

PREREQUISITES
  • Understanding of ideal gas laws, specifically pV = constant in isothermal conditions.
  • Knowledge of thermodynamic concepts such as adiabatic processes and internal energy.
  • Familiarity with specific heat capacities, Cp and Cv.
  • Basic algebra and logarithmic manipulation skills.
NEXT STEPS
  • Study the first law of thermodynamics and its application to adiabatic processes.
  • Learn about the derivation of the ideal gas law and its implications in thermodynamics.
  • Explore the relationship between temperature, pressure, and volume in adiabatic processes.
  • Investigate the significance of specific heat capacities in thermodynamic equations.
USEFUL FOR

Students of thermodynamics, physics enthusiasts, and anyone seeking to understand the behavior of gases under adiabatic conditions.

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Homework Statement


The relationship between pressure and volume of an ideal gas is expressed as pv=constant in a reversable isothermal condition. Show that the relationship between pressure and volume of the same gas is expressed as pV^gamma=constant in a reversible adiabatic condition where gamma=Cp,m/Cv,m.

Homework Equations



gamma=Cp,m/Cv,m.
pV^gamma=constant, rev. adiabatic
pv=constant, rev. ideal

The Attempt at a Solution


p1v1^(Cpm/Cvm)=p2v2^(Cpm/Cvm) take ln and mult both sides by the Cvm/Cpm
ln p1v1 = ln p2v2 e to both sides
p1v1=p2v2
p1v1/p2v2 = 1
 
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please answer it if you have better than these.
your's thankfully milan talaviya
 
Hello Milan, welcome to PF.

You have to show that pVγ= constant assuming a reversible adiabatic process on an ideal gas.

What is an adiabatic process? How does the internal energy change in an adiabatic process? What are Cp and Cv?

ehild
 
milan talaviya said:

The Attempt at a Solution


p1v1^(Cpm/Cvm)=p2v2^(Cpm/Cvm) take ln and mult both sides by the Cvm/Cpm
ln p1v1 = ln p2v2 e to both sides
p1v1=p2v2
p1v1/p2v2 = 1
You haven't proved anything here. For one, you've made an algebra mistake. The more serious error is that you started with what you're supposed to be proving. That sort of argument isn't valid logically.
 
milan talaviya said:

Homework Statement


The relationship between pressure and volume of an ideal gas is expressed as pv=constant in a reversable isothermal condition. Show that the relationship between pressure and volume of the same gas is expressed as pV^gamma=constant in a reversible adiabatic condition where gamma=Cp,m/Cv,m.




Homework Equations



gamma=Cp,m/Cv,m.
pV^gamma=constant, rev. adiabatic
pv=constant, rev. ideal



The Attempt at a Solution


p1v1^(Cpm/Cvm)=p2v2^(Cpm/Cvm) take ln and mult both sides by the Cvm/Cpm
ln p1v1 = ln p2v2 e to both sides
p1v1=p2v2
p1v1/p2v2 = 1
The adiabatic condition that you have to prove is not:

(PV)^{\frac{C_p}{C_v}} = \text{constant}

Rather, it is :

PV^{\frac{C_p}{C_v}} = \text{constant}

which means:

\frac{P_1}{P_2} = (\frac{V_2}{V_1})^{\frac{C_p}{C_v}}

1. Start with the first law and find an expression for dU in terms of PdV (hint: what is dQ if it is adiabatic?).

2. Then express dU in terms of dT and substitute your answer in 1. for dU.

3. Finally express dT in terms of d(PV). (hint: use R = Cp-Cv).

AM
 

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