How to Derive Van der Waals Equations from Thermodynamic Relations?

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SUMMARY

The discussion focuses on deriving the Van der Waals equations from thermodynamic relations for a pure substance. Key equations include the fundamental relation (1) Tds = du + pdv, and the specific forms of the Van der Waals equations (3) T(v-b)^{\alpha} = constant and (4) p + \frac{a}{v^{2}} \approx T^{\frac{1+\alpha}{\alpha}}. The participant successfully derived p + \frac{a}{v^{2}} = \frac{RT}{v-b} = T(\frac{\partial p}{\partial T})_{v} and \frac{a}{v^{2}} = (\frac{\partial u}{\partial v})_{T}, indicating progress in understanding the relationships between these equations.

PREREQUISITES
  • Understanding of thermodynamic relations, specifically Tds = du + pdv.
  • Familiarity with the Van der Waals equation of state.
  • Knowledge of specific heat at constant volume (c_{v}) and its implications.
  • Basic calculus skills for differentiation and integration.
NEXT STEPS
  • Study the derivation of the Van der Waals equation from the ideal gas law.
  • Learn about the implications of specific heat (c_{v}) in thermodynamic processes.
  • Explore the concept of partial derivatives in thermodynamics, particularly (\frac{\partial p}{\partial T})_{v}.
  • Investigate the physical significance of the parameters 'a' and 'b' in the Van der Waals equation.
USEFUL FOR

Students and professionals in thermodynamics, particularly those studying physical chemistry or engineering, will benefit from this discussion. It is especially relevant for those working with real gases and the Van der Waals equation.

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Homework Statement



For any Pure Substance, use the relation (1) to show that for a Van der Waals gas, over a range of conditions where c_{v} is effectively constant, that equation (2) gives equations (3) and (4)

Homework Equations



(1) ~ Tds = du + pdv

(2) ~ c_{v}dT + T \frac{\partial p}{\partial t}_{v}dv = 0

(3) ~ T(v-b)^{\alpha} = constant

(4) ~ p + \frac{a}{v^{2}}\approxT^{\frac{1+\alpha}{\alpha}}

(5) ~ \alpha=\frac{R}{c_{v}}

(6) ~ (p + \frac{a}{v^{2}})(v-b)=RT

The Attempt at a Solution



I really haven't got a clue where to go with this one, this question obviously has something to do with c_{v}.

I was thinking for the first part since its equal to a constant then maybe integration or diferrentiation will come into this at some point. As for the second part i haven't got the slightest clue where to go so any tips would be nice.

I've written down all the equation i think could possibly come into play here, and have tried rearranging them but have not got anywhere with this yet. I can derive equation (2) from equation (1) but i can't see that being much use

I'm new round here and would like to apologise for any thing that I've done wrong

Thanks a lot
 
Last edited:
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i have managed to show that

p+\frac{a}{v^{2}}=\frac{RT}{v-b}=T(\frac{\partial p}{\partial T})_{v}

and that

\frac{a}{v^{2}} = (\frac{\partial u}{\partial v})_{T}

but am now unsure where to go or if this is even the right path to take
 

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