How To Design Solonoid Coil for AC Voltage

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SUMMARY

This discussion focuses on designing a solenoid coil for 240 VAC applications, specifically addressing the selection of wire gauge (SWG) and the calculation of turns required for the coil. The user specifies a target impedance (Zcoil) of 10k ohms and seeks guidance on calculating resistance and inductance based on wire diameter. Key equations include Zcoil = R + j XL and XL = 2 * π * fHz * L, highlighting the relationship between resistance, inductance, and reactance in AC circuits. The discussion emphasizes the importance of wire diameter in optimizing coil design for cost and performance.

PREREQUISITES
  • Understanding of AC circuit fundamentals, including impedance and reactance.
  • Familiarity with solenoid coil design principles.
  • Knowledge of wire gauge (SWG) and its impact on resistance and inductance.
  • Basic mathematical skills for calculating resistance and inductance.
NEXT STEPS
  • Research the formula for calculating solenoid coil inductance based on turns and wire diameter.
  • Learn about the impact of wire gauge on resistance and inductance in AC applications.
  • Explore practical examples of solenoid coil design for different voltage applications.
  • Investigate tools for simulating AC circuit behavior, such as LTspice or Multisim.
USEFUL FOR

Electrical engineers, hobbyists designing solenoid coils, and anyone involved in AC circuit design and optimization.

bhavu21fri
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Hello Friends,

Can you help to solve the problem of my solenoid coil as before i created 12VDC coil & its working fine thanks for that help guys. but now i want 240 VAC solenoid coil. so can you please help me which SWG I have to select. how many turns have to select..i want the equitation how to calculate it.

Voltage is 240VAC
Ohms 10000

Thank You Friends
 
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The current through an AC coil is limited by the coil resistance, R, and the coil inductance, L, in series.
Zcoil = R + j XL The reactance, XL, is proportional to power frequency, XL = 2 * π * fHz * L.

If you halve the cross section area of the wire, you will be able to wind twice the length on the former, the resistance will rise by four times, (half the area and twice the length), the inductance will also rise by four times since the inductance is proportional to the square of the number of turns.

You have specified “Ohms 10000” so I assume you want Zcoil = 10k
You must calculate the resistance and inductance of the coil for different wire diameters and solve for the diameter that gives the minimum cost of wire. Then √(R2 + XL2) = 10k
 
Baluncore said:
The current through an AC coil is limited by the coil resistance, R, and the coil inductance, L, in series.
Zcoil = R + j XL The reactance, XL, is proportional to power frequency, XL = 2 * π * fHz * L.

If you halve the cross section area of the wire, you will be able to wind twice the length on the former, the resistance will rise by four times, (half the area and twice the length), the inductance will also rise by four times since the inductance is proportional to the square of the number of turns.

You have specified “Ohms 10000” so I assume you want Zcoil = 10k
You must calculate the resistance and inductance of the coil for different wire diameters and solve for the diameter that gives the minimum cost of wire. Then √(R2 + XL2) = 10k
Thank you for your replay,

I would like to appreciate if you explain with an example.. because i m new & its very hard to understood. or give some link or document for reference.

My bobbin length is 18mm & radius is 4 mm

Again Thank you very much sir
 
Last edited:

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