How to Determine the Coefficients of a Cubic Function with Given Conditions?

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SUMMARY

The discussion focuses on determining the coefficients a, b, c, and d of a cubic function f(x) = ax³ + bx² + cx + d, given specific conditions: a relative maximum at (3,3), a relative minimum at (5,1), and an inflection point at (4,2). The first derivative f'(x) must equal zero at the maximum and minimum points, leading to the form f'(x) = 3a(x-3)(x-5). The second derivative f''(x) must equal zero at the inflection point, providing a system of equations to solve for the coefficients.

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Homework Statement


Find a,b,c, and d such that the cubic f(x)=[tex]ax^{3}+bx^{2}+cx+d[/tex]satisfies the indicated conditions.

Relative maximum (3,3)
Relative minimum (5,1)
Inflection point (4,2)

Homework Equations





The Attempt at a Solution




I am so lost as to how to do this :/.

Its a polynomial so f ' (x) must = 0 at x=3 and x=5 (can't not exist), and I also know that the derivative of f(x) will be a function of degree 2, which can have at most two roots. Thus the function must be of the form a(x-3)(x-5)=f ' (x), right?

I know that the second derivative is defined for all x (can't have negative exponents, they would become constants before that point). And that f '' (x)=0 at x=4...

I just can't see how to piece it all together. Can someone help me out?
 
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Work out the explicit form of the first and second derivatives of f. Then plug in x=3 and x=5 into the first derivative, which you said must be zero. Plug in x=4 into the second derivative, which again, you said must be zero. This will give you 3 equations in 3 unknowns, which you can solve.
 
[tex]f'(x)=3a(x-3)(x-5)\equiv 3ax^2 +2bx +c[/tex]

is a place to start.
 

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