How to Determine the Masses of Objects from an Acceleration vs. Force Graph?

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To determine the masses of objects 1 and 3 from the acceleration versus force graph, the relationship F=ma is applied, indicating that the slope of the graph represents mass. Given that the mass of object 2 is 0.150 kg, the slopes of the lines for objects 1 and 3 can be compared to that of object 2 to find their respective masses. By analyzing the slopes of the graph, the mass of each object can be inferred based on their proportionality to the known mass of object 2. The discussion emphasizes understanding the slope's significance in determining mass from the graph. Accurate interpretation of the graph is crucial for solving the problem effectively.
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Homework Statement



The figure (Intro 1 figure) shows an acceleration-versus-force graph for three objects pulled by rubber bands. The mass of object 2 is 0.150 kg. What are the masses of objects 1 and 3?
(I've attached the figure...hopefully it will show up)

Homework Equations


F=ma

The Attempt at a Solution


I'm super lost on this one...could use all the help I can get!
 

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ScullyX51 said:

Homework Statement



The figure (Intro 1 figure) shows an acceleration-versus-force graph for three objects pulled by rubber bands. The mass of object 2 is 0.150 kg. What are the masses of objects 1 and 3?
(I've attached the figure...hopefully it will show up)

Homework Equations


F=ma

The Attempt at a Solution


I'm super lost on this one...could use all the help I can get!

F = M*a

This means that

F_{(a)} = m * a

That means that the slope of the F is the mass as in

\frac{dF_{(a)}}{da} = m * \frac{da}{da} = m

So if the slope of 2 is given as .15 kg and on the graph it has a slope of ...?
Then the slope of 1 and 3 compared to 2 should reflect their masses.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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