How to do the indefinite integral

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The discussion centers on solving the improper integral of e^(1/x)/x^3. The original poster struggled with various methods, including integration by parts and substitution, without success. They proposed splitting the integral into (1/x) * [(1/x^2)e^(1/x)] for integration by parts, suggesting a u-substitution with u = 1/x. After further attempts, they found that the substitution worked effectively, leading to a solution. The conversation highlights the importance of u-substitution in tackling complex integrals.
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Homework Statement


I hope someone can help me with this integral. It is really an improper integral, but I cannot figure out how to do the indefinite integral on it:

integral[e1/x/x3].

Any help would be appreciated, thanks.



Homework Equations


?


The Attempt at a Solution



I tried integration by parts, substitution and using the table of integrals. I couldn't get any of them to work.
 
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I would be included to split it up as (1/x) *[ (1/x^2)*e^(1/x)] and try integration by parts on that. IOW, u = 1/x, and dv = (1/x^2)*e^(1/x)dx.

I don't know that this would work, but that's what I would start with.
 


This is definately a U substitution problem, when things are kinda odd inside an exponential, its the best method to try.

pick u=1/x,
that means du= (-1/x^2) dx.

so
\int \frac{e^{1/x}}{x^{3}} dx = \int \frac{-1}{x} e^{1/x}(\frac{-1}{x^{2}}dx)
 


Thank you so much! The substitution did the trick!
 


perfect. Now if only I could get help with my cray cray math.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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