The indefinite integral and its "argument"

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Michael Santos
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Homework Statement


The indefinite integral $$\int \, $$ and it's argument.
The indefinite integral has a function of e.g ## \cos (x^2) \ ## or ## \ e^{tan (x)} \ ##
If the argument of ## \cos (x^2) \ ## is ## \ x^2 \ ## then the argument of ## \ e^{tan(x)} \ ## is ## \ x \ ## or ## \ tan (x) \ ## ?

Homework Equations

The Attempt at a Solution

 
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Hi,

Both are examples of the kind ##f\left( g(x)\right)\ ##.

The argument for ##f()##, the cosine function ##\cos()##, is ##x^2##, so ##g(x) = x^2##.

Similarly, the argument for exponentiation ## f() = \exp() \ ## is ##g(x) = \tan(x)##.

The integrand in both cases is ##f##, so you integrate ##\int f(g(x)) \, dx ##
 
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BvU said:
Hi,

Both are examples of the kind ##f\left( g(x)\right)\ ##.

The argument for ##f()##, the cosine function ##\cos()##, is ##x^2##, so ##g(x) = x^2##.

Similarly, the argument for exponentiation ## f() = \exp() \ ## is ##g(x) = \tan(x)##.

The integrand in both cases is ##f##, so you integrate ##\int f(g(x)) \, dx ##
What if both functions are to be integrated
BvU said:
Hi,

Both are examples of the kind ##f\left( g(x)\right)\ ##.

The argument for ##f()##, the cosine function ##\cos()##, is ##x^2##, so ##g(x) = x^2##.

Similarly, the argument for exponentiation ## f() = \exp() \ ## is ##g(x) = \tan(x)##.

The integrand in both cases is ##f##, so you integrate ##\int f(g(x)) \, dx ##
If both functions are to be integrated what is the argument to integrate?