How to Evaluate and Solve Riemann Sums for Integration: Step-by-Step Guide

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Homework Statement


Evaluate and give an exact answer.

[tex]$\int_{0}^{\frac{Pi}{2}\right)}cos^2(2*Pi*n*x)dx[/tex] where n is a positive integer.


Homework Equations





The Attempt at a Solution


[tex](change)x=\frac{b-a}{n}\right)=\frac{Pi}{2n}\right)[/tex]
and...
[tex]x_i=a+i(change)x[/tex]

I'm not sure how to write a Riemann Sum in latex code, so I'll be using "S" as the notation for the Riemann Sum (i=1, n): f(x_i)*(b-a)/n

I used the limit as n -> oo definition of an integral:

[tex]$\int_{0}^{\frac{Pi}{2}\right)}cos^2(2*Pi*n*x)dx=lim(n->oo)S[f(x_i)(\frac{b-a}{n}\right))][/tex]

Next I substituted the values of [tex]x_i[/tex]:

[tex]lim(n->oo)S[f(\frac{ib}{n}\right))(\frac{Pi}{2n}\right))][/tex]

Then evaluated [tex]f(x_i)[/tex]:

[tex]lim(n->oo)S[cos^2(2*Pi*n*\frac{Pi}{2n}\right)][/tex]

Here is where i get a bit confused. In the example with n-subintervals that I worked through in my book, it substituted the value of the Riemann sum of i using the power of sums formula, however, I end up with "i" inside of the cosine function, and am not sure how to finish evaluating the integral.

Other examples in the book had the value of n defined, thus making the integration process much more simple.

Am I even doing the right thing? Bare with me, my integration is self taught.
 
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Why are you trying to change to Riemann sums? That is, at best, a very difficult way of evaluating integrals! (Though excellent for thinking how to set up integrals for applications.)

Do you know the anti-derivatives of sine and cosine themselves? If so you can use the trig identity [itex]cos^2(\theta)= (1/2)(1+ cos(2\theta)[/itex].
 

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