How to evaluate this integral?

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SUMMARY

The integral under discussion is defined as \int_{-\infty}^{\infty} \sin {( 2 \pi y )} \cdot e^{- \frac{(x-y)^2}{4 \nu t}} dy, where x is constrained between 0 and 1, \nu is a positive constant, and t is positive. The initial attempts included substitution and integration by parts, but these methods did not yield a solution. A suggested approach involves using the Gaussian integral and trigonometric identities to simplify the sine term, ultimately leading to the conclusion that the sine component integrates to zero.

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Homework Statement



[tex]\int_{-\infty}^{\infty} \sin {( 2 \pi y )} \cdot e^{- \frac{(x-y)^2}{4 \nu t}} dy[/tex]

x is between 0 and 1.
[itex]\nu[/itex] is a positive constant.
t is positive.

Homework Equations


The Attempt at a Solution



I tried substituting one variable for x-y, and integration by parts. So far, I've gotten nowhere. Can someone tell me which direction to go?

Thanks.

Edit: Also tried considering the Gaussian integral. But when I change the integration variable to get [itex]e^{u^2}[/itex], there's also a Sin term present. I tried to use integration by parts to get rid of that, but couldn't.
 
Last edited:
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I haven't worked this out, but what I'd try is starting with u=x-y and expand the sin using a trig identity. Argue the sin u term will integrate to 0 and use
$$\cos \theta = \frac{e^{i\theta}+e^{-i\theta}}{2}$$ on the other term.
 

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