How to find acceleration without mass?

  • Thread starter Thread starter trollphysics
  • Start date Start date
  • Tags Tags
    Acceleration Mass
AI Thread Summary
To find acceleration without mass, one can analyze a mass on a slope using a free body diagram. The equation ma = mg sin(theta) - mu*N can be derived, where N is the normal force and can be expressed as N = mg cos(theta). By substituting and canceling the mass (m), the acceleration formula simplifies to a = g sin(theta) - mu*g cos(theta). This approach illustrates that mass can be eliminated when using friction (mu) and the angle of the slope (theta). Understanding this concept is crucial for solving problems related to motion on inclined planes.
trollphysics
Messages
7
Reaction score
0
Can someone explain to me how it is done? I know you cancel the m's out in a formula but how?
 
Physics news on Phys.org
Welcome to PF.

Your question is too vague for anyone to give a meaningful answer. If there is a specific context in which you need to know how to solve for acceleration, by all means post it.
 
differientiate velocity with time?
 
cepheid said:
Welcome to PF.

Your question is too vague for anyone to give a meaningful answer. If there is a specific context in which you need to know how to solve for acceleration, by all means post it.
no i mean like on a slope. My teacher said that you don't need mass if you have M = mu. So on a 45 degree angle ramp. The delta x would be 30m. Then you would need you can cancel out the m's in a equation.
quietrain said:
differientiate velocity with time?
no time. Just are given angle, delta x, mu
 
I think I understand what the question is. If I understand right, there's a mass on a sloped plane and there's a way to solve for the acceleration of the mass down it in terms of g, mu, and theta.

If you set up a free body diagram of the problem, you'll get the equation ma=mg sin(theta) - mu*N, where N is the normal force. N = mg cos(theta), so when you substitute and cancel the m's everywhere, you get:

a = g sin(theta) - mu*g cos(theta)

I think this is what you mean. In any case, try being more clear in your initial post next time.
 
You are also implying Einstein's Equivalence Principle...ALL masses accelerate at "g" at the surface of the earth...that is, it happens that gravitational and inertial acceleration are the same...
 
Just a thought, though it may be way off. Related to what Naty said. It sounds to me like the poster might be thinking of formulae for gravitational attraction relative to a specific body of known mass. If so, the process you may be looking for is:

F = (G.m1.m2)/d²
F = ma

So for a given mass:

a = F/m
= ((G.m1.m2)/d²)/m
= Gm/d²

Useful for calculating the orbits of satellites around the Earth or planets around stars etc.
 

Similar threads

Replies
5
Views
2K
Replies
10
Views
2K
Replies
8
Views
2K
Replies
33
Views
2K
Replies
7
Views
2K
Back
Top