How to Find Charge Stored on Capacitors in Series?

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SUMMARY

In a series circuit with two capacitors, one 7.2 µF and the other 16 µF, connected to a 15 V battery, the equivalent capacitance (C-eq) is calculated to be 5.0 µF. The charge (Q) stored on both capacitors is the same due to the nature of series connections. The relationship between voltage (V), charge (Q), and capacitance (C) is expressed as V = Q/C. The user successfully resolved their confusion regarding the charge calculation by applying these formulas correctly.

PREREQUISITES
  • Understanding of capacitor behavior in series circuits
  • Familiarity with the formula V = Q/C
  • Knowledge of equivalent capacitance calculation
  • Basic electrical concepts, including voltage and charge
NEXT STEPS
  • Study the derivation of the equivalent capacitance formula for capacitors in series
  • Learn about the energy stored in capacitors and its calculation
  • Explore practical applications of capacitors in electronic circuits
  • Investigate the effects of varying capacitance values on charge distribution
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Students and professionals in electrical engineering, electronics enthusiasts, and anyone seeking to understand capacitor behavior in series circuits.

mli273
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1. Two capacitors, one 7.2 \muF the other 16 \muF, are connected in series across a 15 V battery.

Find the charge stored on 7.2 \muF capacitor.
Find the charge stored on 16 \muF capacitor.


2. C-eq =5.0\muF and V=Q/C and \epsilon=Q(1/C-eq)


3. I know that both Q values should be the same because the capacitors are in series, but I'm not sure how to go about using the formulas I have. I've tried averages of the two charges, and that didn't work. What am I missing? Thanks in advance!
 
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Nevermind, figured it out on my own.
 

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