How to find electric potential given only velocity

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jlmccart03
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Homework Statement


Given v = v=4.8×105m/s find the change in electric potential.

Homework Equations


ΔV = Vf-Vi = -W/q

The Attempt at a Solution


I really don't know any other formula that has the use of velocity to find ΔV. So how does velocity end up into the mix in finding ΔV?
 
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There has to be more to the given problem than what you've written. A velocity alone says nothing about what the scenario is. What is the complete problem statement?
 
gneill said:
There has to be more to the given problem than what you've written. A velocity alone says nothing about what the scenario is. What is the complete problem statement?
Here is a picture.
upload_2017-2-14_19-6-10.png
 
jlmccart03 said:

Homework Statement


Given v = v=4.8×105m/s find the change in electric potential.

Homework Equations


ΔV = Vf-Vi = -W/q

The Attempt at a Solution


I really don't know any other formula that has the use of velocity to find ΔV. So how does velocity end up into the mix in finding ΔV?
Whelp, that post didn't go so well.

It's good to know that v=v, that's always a good start... :smile:

A potential difference produces an accelerating force on a charged particle, not just a "velocity" in isolation. There needs to be a lot more to this question that you haven't posted so far?

EDIT -- gneill beat me to it (again)...
 
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jlmccart03 said:
Here is a picture.View attachment 113222
Oh, that's a lot easier. What do you know about the units of energy "eV" (electron Volts) and how you express the kinetic energy of a moving electron...?
 
berkeman said:
Oh, that's a lot easier. What do you know about the units of energy "eV" (electron Volts) and how you express the kinetic energy of a moving electron...?
Well units of energy eV is 1.6*10^-19 J and KE = 1/2mv^2 for an electron.