1. Here is the sketch: http://i.stack.imgur.com/0s1is.jpg The sketch is supposed to be side-view of the path of the object. The following values are known: - r - radius of the circle that describes the path AB of the object - a - angle that characterizes the part of a circle that describes the path AB of the point - m - mass of the point - V0 - velocity The dashed line is the object's trajectory after it leaves AB. N is the normal force, T is friction and g is the gravitational acceleration. 2. What I need to find out: 1. Equation of motion for AB 2. Equation of motion for BC 3. velocity at B 4. The distance DC 3. The attempt at a solution I was able to solve this problem partially when AB is a straight line and 'a' represents the angle between AB and AD. So far I could come up with only this: m*(x)'' = -T-mgsin(?) <- in place of the question mark I would need the angle between AB and AD m*(y)'' = N-mgcos(?) N = mgcos(?) T = μN = μmgcos(?) (x)'' = -g(μcos(?) + sin(?)) (x)' = -gt(μcos(?) + sin(?)) + c1 x = ((-9t^2)/2)(μcos(?) + sin(?)) + c1 + c2 where μ is the coefficient of friction. x and y are functions of the x and y coordinates with respect to time. How do I deal with the fact the ramp is no longer a straight line but a curved line? I need to solve this problem, otherwise I cannot apply for taking the exam in mechanics 1. I appreciate any thoughts. Thank you very much for your help. By the way, I'm so happy I found this place and I also signed up for a free membership at educator.com. This is awesome, I never had access to this much knowledge in form of video-courses. Thank you physicsforum.com and educator.com!!