How to find integrals of parent functions without any horizontal/vertical shift?

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To find integrals of parent functions without horizontal or vertical shifts, the integral of a function in the form Cxp (where p ≠ -1) is calculated as Cxp+1/(p+1). The main challenge arises when approximating values like 9^{1/7} and 14^{8/7} using basic calculators limited to addition, subtraction, multiplication, and division. Techniques suggested include polynomial expansion and iterative methods to refine approximations. The discussion emphasizes the need for adequate approximations to compute these values accurately. Overall, the focus is on overcoming computational limitations to find integrals effectively.
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TL;DR Summary: How to find integrals of parent functions without any horizontal/vertical shift?

Say you were given the equation :
Screenshot 2023-05-27 170512.png

How would you find :
Screenshot 2023-05-27 170938.png
with a calculator that can only add, subtract, multiply, divide

Is there a general formula?
 
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You have a function of the form Cxp where p ≠ -1.
The integral is Cxp+1/(p+1)
 
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The difficulty here is to compute (adequate approximations to) 9^{1/7} and 14^{8/7} = 14 \cdot 14^{1/7} using "a calculator that can only add, subtract, multiply, divide".
 
pasmith said:
The difficulty here is to compute (adequate approximations to) 9^{1/7} and 14^{8/7} = 14 \cdot 14^{1/7} using "a calculator that can only add, subtract, multiply, divide".
1261/7≈1281/7=2
One could then do the polynomial expansion (2-x)7=126 and throw away higher terms to find corrections. Or do some iteration.
 
First, I tried to show that ##f_n## converges uniformly on ##[0,2\pi]##, which is true since ##f_n \rightarrow 0## for ##n \rightarrow \infty## and ##\sigma_n=\mathrm{sup}\left| \frac{\sin\left(\frac{n^2}{n+\frac 15}x\right)}{n^{x^2-3x+3}} \right| \leq \frac{1}{|n^{x^2-3x+3}|} \leq \frac{1}{n^{\frac 34}}\rightarrow 0##. I can't use neither Leibnitz's test nor Abel's test. For Dirichlet's test I would need to show, that ##\sin\left(\frac{n^2}{n+\frac 15}x \right)## has partialy bounded sums...

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