How to Find Maclaurin Polynomials for ln(x) in Sigma Notation?

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Homework Help Overview

The discussion revolves around finding the Maclaurin polynomials for the function f(x) = ln(1+x) up to the 4th order and expressing them in sigma notation. Participants are exploring the derivatives of the function and their implications for constructing the polynomial.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to compute derivatives of ln(1+x) and express the resulting polynomial in sigma notation. There is uncertainty about finding derivatives and the relationship between integration and differentiation.

Discussion Status

Some participants have provided insights into the derivatives and their relationship to integration. There is an ongoing exploration of the correct function to differentiate, with some clarity emerging around the derivatives of ln(1+x) as participants engage with the problem.

Contextual Notes

There is a noted confusion regarding the function to differentiate, initially referencing ln(x) instead of ln(1+x). Participants are also questioning the process of finding derivatives and the transition to sigma notation.

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Homework Statement



Find the Maclaurin polynomials of orders n=0, 1, 2, 3, and 4, and then find the nth Maclaurin polynomials for the function in sigma notation:

f(x)= ln(1+x)


Homework Equations



pn(x)= f(0) + f'(0)x + [f''(0)/2!](x)^2 +[f'''(0)/3!](x)^3 + ... + [f^(n)(0)/n!](x)^n


The Attempt at a Solution



I know that I need to find up to the 4th derivative using f(x)=ln(x) and then simply use the maclaurin polynomial equation up to a certain point for n = 0, 1, 2, 3, 4 .. n.

The only problem is I can't remember how to FIND derivatives of ln(x)!
I don't really understand how to find the nth polynomial in sigma notation either..

Thank you!
 
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What integrates to give ln(x)? (How is it defined?)
The nth polynomial bit will probably become clearer once you've written down a few of the derivatives.
 
Well, I thought (1/x) integrates to ln(x), but I wasn't sure about the derivative...
 
So what's the realtionship between integrating and differentiating?
 
OH okay i just realized at the beginning of the problem i was referring to ln(x+1) and then somehow i changed it to ln(x). i understand about the relationship between ln(x) and 1/x, i just need help with the derivative of ln(x+1)

thank you!
 
Try letting u=x+1
 
soo.. ln(u)du =1/(u) ? so its just 1/(x+1) ?

wow, i thought it was a lot harder for some reason.
 
That's right.
 

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