How to find magnitude of centripetal acceleration and of net force?

  • Thread starter starplaya
  • Start date
  • #1
8
0

Homework Statement


A ferris wheel at a carnival has a radius of 12 m and turns so that the speed of the riders is 8m/s
a) what is the magnitude of the centripetal acceleration of the riders?
b) what is the magnitude of the net force required to produce this centripetal acceleration for a rider with a mass of 70kg?


Homework Equations



Centripetal acceleration = v^2/r
F = ma
Fnet = N - W = m(centripetal acceleration)

The Attempt at a Solution



centripetal acceleration = 8^2/ 12 = 5.33 m/s^2
 

Answers and Replies

  • #2
Doc Al
Mentor
44,986
1,258
centripetal acceleration = 8^2/ 12 = 5.33 m/s^2
Looks good.
 
  • #3
8
0
Looks good.
so, 5.33 m/s^2 would be the answer for part A and for part B i just multiply the acceleration by the mass?
 
  • #4
Doc Al
Mentor
44,986
1,258
so, 5.33 m/s^2 would be the answer for part A and for part B i just multiply the acceleration by the mass?
That's correct.
 
  • #5
8
0
Boy was I over thinking that. Thanks a lot for the clarification
 

Related Threads on How to find magnitude of centripetal acceleration and of net force?

Replies
4
Views
2K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
1
Views
14K
Replies
1
Views
2K
Replies
3
Views
8K
Replies
1
Views
4K
Replies
4
Views
542
Replies
4
Views
13K
  • Last Post
Replies
21
Views
2K
Replies
1
Views
1K
Top