- #1
jun9008
- 13
- 0
It's my first time here so I guess I have to introduce myself first.
I am a junior in high school taking Calculus BC and Physics B (taking Physics C next year).
Currently, as of September 29, 2008, my class is learning of Polar equations.
We just went over basics but I am not perfectly grasping the concept on using polars.
One of the question I received during class was:
r=1/2 + sin([tex]\theta[/tex]
Now, without using calculator, how do I find the area of the equation which excludes the overlaping part.
I know that
A=1/2[tex]\int[/tex]r^2 d[tex]\theta[/tex]
but here we would subtract the inner area.
No point in using calculator;;; I cannot check my answer either since my teacher said the right answer choice is not shown (it is a multiple choice question).
ps. I don't know how to use the "tex" thing so...
I am a junior in high school taking Calculus BC and Physics B (taking Physics C next year).
Currently, as of September 29, 2008, my class is learning of Polar equations.
We just went over basics but I am not perfectly grasping the concept on using polars.
One of the question I received during class was:
r=1/2 + sin([tex]\theta[/tex]
Now, without using calculator, how do I find the area of the equation which excludes the overlaping part.
I know that
A=1/2[tex]\int[/tex]r^2 d[tex]\theta[/tex]
but here we would subtract the inner area.
No point in using calculator;;; I cannot check my answer either since my teacher said the right answer choice is not shown (it is a multiple choice question).
ps. I don't know how to use the "tex" thing so...
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