How to find the density function of a random variable with a given distribution?

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Homework Help Overview

The discussion revolves around finding the density function of a random variable derived from another random variable, specifically transforming a uniformly distributed variable Y into Z via the tangent function. The original poster presents a similar problem involving a linear transformation of a uniformly distributed variable X.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the transformation of the uniform distribution through the tangent function and question how to derive the density function for Z. There are attempts to relate the problem to a previously solved example involving a linear transformation of a uniform variable.

Discussion Status

The discussion is ongoing, with participants questioning assumptions and clarifying the nature of the uniform distribution. Some guidance has been provided regarding the density function of Y, but there is no consensus on the approach to finding the density function of Z.

Contextual Notes

There is a noted lack of clarity in the original post regarding the problem's context, and some participants express confusion about the assumptions being made. The original poster is encouraged to share their previous efforts in solving the problem.

nhrock3
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[tex]Y-U(-2\pi,2\pi)[/tex]
find the density function of z=tan(Y)
?

i had a similar question

X-U(0,1)
find the density function of W=a+bx
the solution is
W-U(a,a+b)

how to solve the first question ??
 
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Please, tell us what you are talking about!

I think that you are saying that uniformly distributed between [itex]-2\pi[/itex] and [itex]and [itex]2\pi[/itex], but I have to guess that bcause you didn't even say this was a probability question!<br /> <br /> <blockquote data-attributes="" data-quote="nhrock3" data-source="post: 2559729" class="bbCodeBlock bbCodeBlock--expandable bbCodeBlock--quote js-expandWatch"> <div class="bbCodeBlock-title"> nhrock3 said: </div> <div class="bbCodeBlock-content"> <div class="bbCodeBlock-expandContent js-expandContent "> [tex]Y-U(-2\pi,2\pi)[/tex]<br /> find the density function of z=tan(Y)<br /> ? </div> </div> </blockquote> What have you done? You know that you are to show what efforts you have already made don't you?<br /> <br /> <blockquote data-attributes="" data-quote="" data-source="" class="bbCodeBlock bbCodeBlock--expandable bbCodeBlock--quote js-expandWatch"> <div class="bbCodeBlock-content"> <div class="bbCodeBlock-expandContent js-expandContent "> i had a similar question<br /> <br /> X-U(0,1)<br /> find the density function of W=a+bx<br /> the solution is<br /> W-U(a,a+b)<br /> <br /> how to solve the first question ?? </div> </div> </blockquote> What is the density function for Y?[/itex]
 
it is probability question

the density function of Y is distributed evenly
[tex] Y-U(-2\pi,2\pi)[/tex]

i tried to solve it like the example question i showed

but here in tangense i have no idea
because i could find the density by this
(tan(-2pi),tan(2p))
but this is wrong because if we have an interval mutiplication streches it
subtraction moves it to the left
but tangense
i have no idea
 
Since Y itself is uniformly distributed from [itex]-2\pi[/itex] to [itex]2\pi[/itex], its cumulative probability function is [itex]x/(2\pi)[/itex] an its density function is the constant [itex]dY/dx= 1/(2\pi)[/itex]. The density function of Z= tan(Y) is the derivative of tan(Y): [itex]d(tan(x/(2\pi))[/itex].
 
you said facts but how you get to them?
the final solution is
[tex]f_z(t)\frac{1}{\pi(1+t^2)}[/tex]
so its like you said

but i can't see a logical way like in the solved example i showed
?
 

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