How to Find the Expectation Value of Momentum?

  • Thread starter Thread starter mogsy182
  • Start date Start date
  • Tags Tags
    Momentum Value
Join the discussion
Registration is free. Start your own thread to ask a follow-up.
5 replies · 2K views
mogsy182
Messages
16
Reaction score
0

Homework Statement


find expectation value of the momentum fro

SI(x,t) = (1/aPI)^1/4 exp((-x^2)/2a)


Homework Equations


pSI(x,t) = -ih dsi/dx
<SI*[p]SI> = integral SI*pSI dx

The Attempt at a Solution



just need help with the integral
 
Physics news on Phys.org
I'm having a bit of trouble following your notation, but I'm guessing you're trying to calculate:

[tex]<P> = \int_{-\infty}^\infty \psi(p) p \psi^*(p) dp[/tex]

where:

[tex]\psi(p) = \int_{-\infty}^\infty \psi(x) e^{\frac{\imath p x}{\hbar}} dx[/tex]

Which integral do you need help with?

--------
Assaf
http://www.physicallyincorrect.com/"
 
Last edited by a moderator:
yes its the first integral
Im following a soloution to a similar question in my notes and it says something about odd/even function? thanks
 
Have you calculated [tex]\psi(p)[/tex] yet? If so, what was your result? If not, let's start with that.
 
hope you get the notation lol
hopefully this is right

SI(p) = ih(1/aPI)^1/4 ((x/a)exp ((-x^2)/2a)))


what do you use to get the notation on the forum?
 
When you use the operator p on Psi in the integral, a factor of x will pop out when you take the derivative of Psi. Then you'll have something like x times e^(-x^2) and then you should use the properties of even and odd functions to simplify the integral greatly.

Hope that helps