How to find the integral of (3x^3 - 1)/x from 1 to e

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The integral of the function (3x^3 - 1)/x from 1 to e can be simplified using the principle of separating fractions. This leads to the expression ∫ from 1 to e of (3x^2 - 1/x) dx, which is straightforward to integrate. The integration results in the evaluation of the polynomial and logarithmic components, yielding a final answer that can be computed directly. This method effectively demonstrates the utility of algebraic manipulation in integral calculus.

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[tex]\int_{1}^{e} \frac{3x^3-1}{x} dx[/tex]

What method? I haven't seen a problem like this before.
 
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Remember how (a+b)/c = a/c + b/c ? Use a similar principle.
 


Ah, OK so:

[tex]\int_{1}^{e} 3x^2 -\frac{1}{x} dx[/tex]

In which case this becomes a simple integration problem.

Thank you!
 

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