How to find the nth term of this Series.

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The discussion focuses on calculating the Taylor polynomial of degree 4 for the function f(x)=sin(3x) around x=0 and subsequently finding the 156th term of the infinite Taylor Series for g(x)=sin(3x). The participant's polynomial was noted as -4.5x³ + 3, which was questioned for accuracy. To find the nth term, participants suggested analyzing the pattern of the series and using the known expansion of sin(x) around x=0.

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Homework Statement



1. First, calculate the Taylor polynomial of degree 4 for f(x)=sin(3x) about x=0.

2. Then find the 156th term of the infinite Taylor Series for g(x)=sin(3x)

Homework Equations



My Taylor polynomial ended up being -4.5x3+3.

The Attempt at a Solution



I understood part one, but how do I use the nth term for infinite series equation on the polynomial I just developed? Or is it asking something different?
 
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From the terms you calculated, look at the pattern of the formulas and see if you can formulate the expression for an nth term.

Then you'd want n=156

If you know the expansion of sinx about x=0 or how to formulate the nth term, it is a similar exercise.
 
mundane said:

Homework Statement



1. First, calculate the Taylor polynomial of degree 4 for f(x)=sin(3x) about x=0.

2. Then find the 156th term of the infinite Taylor Series for g(x)=sin(3x)

Homework Equations



My Taylor polynomial ended up being -4.5x3+3.

The Attempt at a Solution



I understood part one, but how do I use the nth term for infinite series equation on the polynomial I just developed? Or is it asking something different?

Your degree 4 Taylor polynomial is also a bit off. Is that just a typo?
 

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