How to find the potential difference with constant charge

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SUMMARY

This discussion focuses on calculating the electric field and potential difference in a capacitor with a constant charge density, as opposed to a vacuum. The relevant equations include Gauss's Law, expressed as ∫ E · dA = Q_encl/ε₀, and the potential difference formula V_ab = ∫ E · dl. Participants express uncertainty about adapting these equations to scenarios involving constant charge density, highlighting the need for a clear approach to solving such problems.

PREREQUISITES
  • Understanding of Gauss's Law and its application in electrostatics.
  • Familiarity with electric field concepts and potential difference calculations.
  • Knowledge of charge density and its implications in electric fields.
  • Basic calculus skills for evaluating integrals in physics equations.
NEXT STEPS
  • Study the application of Gauss's Law in non-vacuum scenarios.
  • Learn about the effects of constant charge density on electric fields.
  • Explore advanced electrostatics topics, including dielectric materials.
  • Practice solving problems involving electric fields and potential differences in various charge configurations.
USEFUL FOR

Students in physics, particularly those studying electromagnetism, as well as educators and anyone seeking to deepen their understanding of electric fields and potential differences in capacitors with constant charge density.

mattz205
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Homework Statement


How would i go about finding the electric field and potential difference when there is a constant charge density between the capacitor rather than a vacuum?

Homework Equations


int E dot dA = Qencl/epsilon0
V ab = int E dot dl

The Attempt at a Solution


to be honest I am not really sure where to start this, i know how to find all this when there is a vacuum or dielectric, but what would i do to find it when there is a constant charge density?
 
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mattz205 said:

Homework Statement


How would i go about finding the electric field and potential difference when there is a constant charge density between the capacitor rather than a vacuum?

Homework Equations


int E dot dA = Qencl/epsilon0
V ab = int E dot dl

The Attempt at a Solution


to be honest I am not really sure where to start this, i know how to find all this when there is a vacuum or dielectric, but what would i do to find it when there is a constant charge density?
Please post the problem as stated to you.
 

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