How to Find the Radius for Minimum Surface Area of Cylindrical Cans?

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SUMMARY

The discussion focuses on determining the radius that minimizes the surface area of cylindrical cans with specified volumes ranging from 100 cm³ to 155 cm³. The surface area (SA) of a cylinder is expressed as SA = 2πr² + 2πrh, where r is the radius and h is the height. To find the minimum surface area, one must derive the surface area function with respect to radius, substitute the height using the volume equation V = πr²h, and then differentiate to find critical points. This approach is essential for optimizing material usage in can production.

PREREQUISITES
  • Understanding of calculus, specifically differentiation and critical points.
  • Familiarity with the formulas for the volume and surface area of a cylinder.
  • Basic knowledge of algebra for rearranging equations.
  • Ability to interpret and manipulate mathematical functions.
NEXT STEPS
  • Study the derivation of the surface area formula for a cylinder.
  • Learn how to apply differentiation to find minima and maxima of functions.
  • Practice solving optimization problems involving geometric shapes.
  • Explore real-world applications of calculus in manufacturing and design.
USEFUL FOR

Students studying calculus, engineers involved in product design, and professionals in manufacturing seeking to optimize material usage for cylindrical containers.

superhulk
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i need MAJOR HELP!

this is the problem:

The can do tin can company minimizes costs by construckting cans from the least possible amount of material. this company suppplies many different sizes of cans to packing firms. a designer with the company needs to determine the radius that gives the minimum surface area for cylindrical cans with volumes between 100 cm (cubed) and 155 cm (cubed).



basically i need to know how to find the smallest surface area for the following volumes: 100 300 500 700 900 1100 1300 and 1500 cm(cubed)

can someone pleaseEEEEEEEEEEEEEEEEEE help me
 
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That seems like a mainly APPLIED type Calculus problem. You first need to derive or look in reference material for the surface area for a circular cylinder. Arrange the equation to be surface area as a function of radius. Find the derivative of this surface area function. You are then interested in minimum surface area; find the radius for each case. (someone check my thinking about all that since a long time has passed since I studied Calculus).
 


You have two equations: volume of a cylnder of radius r and height h is \pi r^2h whch must be equal to one of the values you give, and surface area is 2\pi r^2+ 2\pi rh which is what you want to minimize. You can use the first, volume, equation to solve for, say, h, as a function of r and replace that in the second formula.
It might be a good idea to use "V" for the volume rather than one of the numbers you give so you can just plug in a number after you have solved for r and h.

Do you know how to find the max or min of a function by differentiating?
 

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