How to Find the Volume of a Rotating Solid?

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To find the volume of the solid formed by rotating the region defined by f(x) = 2 sin x on the interval [0, π] around the line y = -1, the integration method involves using the formula pi∫(2sin(x) + 1)^2 dx. The discussion highlights confusion regarding the definition of the region, as f(x) alone does not specify a complete area without a clear upper boundary. There is uncertainty about why the line y = -1 is chosen as the axis of rotation instead of the x-axis. Clarification is needed on the boundaries of the region to properly apply the volume formula. Understanding these aspects is crucial for solving the problem correctly.
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Homework Statement


Region: f(x) = 2 sin x on the interval [0, π]. Find the volume of
the 3D solid obtained by rotating this region
about the dashed line y = −1.

Homework Equations



Integration of pi∫(2sin(x) + 1)^2 dx

The Attempt at a Solution



http://www3.wolframalpha.com/Calculate/MSP/MSP85361a550f47a75i0g7800002h3g026g9d9ieg7f?MSPStoreType=image/gif&s=3&w=301&h=35

That does not seem to work. I am completely baffled as to what I am doing wrong.
 
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f(x) = 2 sin x on the interval [0, π] does not define a region. It defines a curve and two limits on the x coordinate. You seem to be assuming the remaining boundary is the line y = -1, but why that rather than, say, the x axis?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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