How to find the wavelength of a particle with mass?

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SUMMARY

The discussion focuses on calculating the de Broglie wavelength of an electron with a speed of 2.2 x 106 m/s. The participant correctly applies the formula for momentum (P = MV) using the mass of the electron (9.11 x 10-31 kg) to find the momentum as 2 x 10-24 kg·m/s. Subsequently, they use the de Broglie wavelength formula (λ = h/p) with Planck's constant (h = 6.62 x 10-34 J·s) to calculate the wavelength as 3.33 x 10-10 m, which is confirmed as a typical result.

PREREQUISITES
  • Understanding of quantum mechanics concepts, specifically de Broglie wavelength
  • Familiarity with the formula for momentum (P = MV)
  • Knowledge of Planck's constant (h = 6.62 x 10-34 J·s)
  • Basic skills in algebra for manipulating equations
NEXT STEPS
  • Study the implications of wave-particle duality in quantum mechanics
  • Learn about the uncertainty principle and its relation to particle wavelength
  • Explore applications of de Broglie wavelength in electron microscopy
  • Investigate the relationship between speed, mass, and wavelength in different particles
USEFUL FOR

Students of physics, particularly those studying quantum mechanics, as well as educators and anyone interested in the wave properties of particles with mass.

nukeman
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Homework Statement



Does the following question ask what my title says? I study pack says "How to find the wavelength of a particle with mass?" So, is the following question good?

Question: What is the deBroglie wavelength of an electrion with a speed of 2.2x10^6 m/s

Answer I got: First, calculate the momentum, P=MV
(9.11x10^-31)(2.2x10^6m/s) = 2x10^-24

So... Wavelength = h/p = 6.62x10^34/2x10^-24

= 3.33x10^-10

Is this correct guys? Thanks!



Homework Equations





The Attempt at a Solution

 
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nukeman said:

Homework Statement



Does the following question ask what my title says? I study pack says "How to find the wavelength of a particle with mass?" So, is the following question good?

Question: What is the deBroglie wavelength of an electrion with a speed of 2.2x10^6 m/s

Answer I got: First, calculate the momentum, P=MV
(9.11x10^-31)(2.2x10^6m/s) = 2x10^-24

So... Wavelength = h/p = 6.62x10^34/2x10^-24

= 3.33x10^-10

Is this correct guys? Thanks!



Homework Equations





The Attempt at a Solution


The method is good - I assume you calculated correctly at each step. That answer is certainly a typical size.
 

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