How to find this answer using logarithmic table?

  • Thread starter Thread starter Dinesh321
  • Start date Start date
  • Tags Tags
    Logarithmic Table
AI Thread Summary
To find the logarithm of a quotient like 3/5840 using a logarithmic table, first express the numbers in scientific notation. The logarithm of a product can be calculated using the formula log(AB) = log(A) + log(B), while the logarithm of a quotient uses log(A/B) = log(A) - log(B). The discussion references a logarithmic table similar to those found in CRC series books, which typically contain logs for values from 0.100 to 0.999. Users are encouraged to consult old Intermediate Algebra textbooks for detailed instructions on using log tables. Understanding the concepts of logarithm, base, and anti-logarithm is essential for mastering this technique.
Dinesh321
Messages
3
Reaction score
0
[Mod Note: moved into homework forum, so template not present][/color]

3/5840=0.00051
How to find this answer using logarithmic table? Thanks in advance.?
 
Physics news on Phys.org
What do you do to find the logarithm of a product ?
And what for the logarithm of a quotient ?
 
What kind of logarithmic table do you have available?
 
I want to find quotient of 3 and 5840.
 
Dinesh321 said:
I want to find quotient of 3 and 5840.

We know.

Now answer our questions.
 
I am using Logarithmic table (of 11th standard student).
 
Dinesh321 said:
I am using Logarithmic table (of 11th standard student).

That doesn't tell us anything. Please describe the table or attach a picture.

And answer BvU too.
 
My guess is the table is similar to the one in the CRC series of books. It's a table of 900 logs (base 10) for values 0.100 to 0.999, to 4 decimal places. The CRC books explain how to use the log tables.
 
You need to convert all of the numbers involved into a form similar to scientific notation. For this problem, 3 = .3 * 101, so log(3) = log(.3 * 101) = log(.3) + log(101) = log(.3) + 1

To calculate the log of a product, use the fact that log(AB) = log(A) + log(B). To calculate the log of a quotient, use the fact that log(A/B) = log(A) - log(B).
 
  • #10
Thanks Mark for answering my question...:wink:... however, it was meant for Dinesh...
 
  • #11
Old textbooks on Intermediate Algebra had good instructions for how to use log tables. Those would be the best way to learn this. Learning to use such tables will require some studying, maybe a couple of weeks if you are new to this; maybe a couple hours or so if you had done it previously. All the while, keep reminding yourself the meaning of LOGARITHM, base, and ANTI-LOG. Not telling you how. I'm just suggesting where to look.
 
  • Like
Likes SammyS
Back
Top