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How To Implement This Function With 2 Input Nand

  1. Apr 27, 2008 #1
    Default How To Implement This Function With 2 Input Nand..
    (+) =XOR


    i tried to :

    F(w,x,y,z)=(w'+x'+y')(+)xyz=(w'+x'+y')' *(xyz) + (w'+x'+y')(xyz)'=
    in the end i get

    what to do know???
    how to transform implement it with a two input line NANDs
  2. jcsd
  3. May 6, 2008 #2
    Well, the word NAND should scream Sum of Products (SOP), so try to get your function to that point, then you can modify it further. After playing around with your function, you should get something like:

    [tex]F = \overline{x} + \overline{y} + (\overline{w})(\overline{z}) + wxyz[/tex]

    (Keep in mind that [tex]A+AB = A[/tex]; your final equation doesn't take that into account).

    I'm going to show you another useful proof:

    [tex]\overline{ABCD} = \overline{A}+\overline{B}+\overline{C}+\overline{D} = (\overline{A}+\overline{B})+(\overline{C}+\overline{D}) = \overline{AB}+\overline{CD} = \overline{(\overline{AB})(\overline{CD})} [/tex]

    The function is also equal to (through DeMorgan):
    [tex]F = \overline{xy ( \overline{ \bar{w} \bar{z} })( \overline{wxyz}) }[/tex]

    Use the proof above on that form of F. Use the proof above to get [tex]\overline{(wxyz)}[/tex], too. Use NANDs as inverters to get w' and z'.
  4. Jan 23, 2010 #3
    I think There is a mistake it should be [tex] \overline{AB}+\overline{CD} = \overline{({AB})({CD})} [/tex]
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